Understanding Dominant and Recessive Traits - AP Biology

A haploid cell is a cell that possesses only a single set of chromosomes (n=23) as opposed to the double set found in somatic cells (2n=46). The gametes (sperm and ova) in humans are examples of haploid cells. Also, the zygote is formed upon fusion of two gametes, and is thus diploid.

Somatic cells in humans have two copies of each chromosome (2n=46) as opposed to haploid cells which have only one set of chromosomes (n=23). Muscle cells are somatic cells, sperm and ova are haploid cells, since they are gametes.

A genotype is the genetic makeup of alleles coding for a characteristic. In this example, a heterozygote has one recessive and one dominant allele, making the genotype Aa. The phenotype is the observable expression of the genotype. Since a heterozygote has one dominant allele and one recessive allele, the dominant allele is exhibited, thus the phenotype is brown hair.

The phenotype is the observable characteristic of an individual. In this example, a homozygous recessive plant will have a white flower phenotype and a genotype of aa.

An allele is a genetic variant of a given trait. Alleles for the given trait within an individual are located at the same genetic locus. The resulting observable characteristic is called a phenotype. Humans are diploid organisms, meaning that they have two copies of each gene, where each copy may be the same or different alleles.

Gregor Mendel carried out experiments using pea plants to discover the fundamental principles of genetics. Louis Pasteur was a microbiologist who is known for his work with vaccines and pasteurization. Both Francis Crick and James Watson are credited for their discovery of the structure of DNA.

The principle of dominance in genetics states that some alleles are dominant and are expressed instead of the recessive allele. Hybrids are crosses between parents with different traits, and genotypes for different eye colors are different.

The correct code for homozygous dominant is TT. Homozygous means the "same alleles," and the dominant allele is a capital letter, which, in this case is "T."

Since B is completely dominant over b, and you obtained a 3:1 ratio of phenotypes, the parents must have been heterozygous, therefore you can represent their genotypes as Bb.

If either parent were BB, you would obtain only brown offspring. If either parent were bb, they would have been white (rather than bronw).

Because the plants are homozygous dominant for color, you need only consider seed shape. Crossing a heterozygous plant with another heterozygous plant will always lead to 75% of offspring in the F1 generation displaying the dominant trait.

All of the offsrping will also be yellow, though this does not directly relate to the answer.

When examining two autosomal dominant traits, a cross between two heterozygous individuals will always produce F1 offspring in the same 9:3:3:1 ratio. Nine of the sixteen are individuals who are dominant for both traits, six are individuals who are dominant for one trait and recessive for the other, and the single individual is recessive for both traits. Three individuals will be yellow with wrinkled seeds, and three will be green with round seeds.

The first cross will produce a generation of double heterozygous flowers. Self-crossing this generation becomes a dihybrid cross problem.

In order to solve this problem, you can use either a punnett square and count the squares that display this phenotype, or you can use probability. Since purple is dominant, three out of four flowers will display the color purple. Since wrinkled is recessive to round, only one out of four flowers will display this phenotype. Since the flowers in question must express both of these traits, we can simply multiply these two fractions together.

You should be familiar with the 9:3:3:1 ratio of dihybrid cross phenotypes. A phenotype of one dominant trait and one recessive trait will always be observed with a frequency.

Dominant alleles are neither better, nor worse than recessive alleles. They are simply expressed in the phenotype of a heterozygous pair. Several deleterious, and even deadly disorders like Huntington's disease, are inherited via an autosomal dominant pattern.

Note that the frequency of an allele or genotype in a population must be determined experimentally, and can be linked to environmental influences, autosomal versus sex-linked patterns, and numerous other factors.

Since one of the parent has blue antennae, we know for that they have a homozygous recessive genotype (bb). The information given in the question does not tell us whether or not the parent with green antennae is homozygous dominant (BB) or heterozygous (Bb). The cross could be set up as either BB x bb or Bb x bb. These two crosses would give you a 0% chance and a 50% chance of having a child with blue antennae, respectively.

BB x bb: Offspring will all be Bb, and cannot show the blue phenotype.

Bb x bb: Half of the offspring will be Bb and half will be bb. Half of the offspring will show the blue phenotype.

If the dog with the unknown genotype is heterozygous, our cross would be: Aa x aa. In this model, A represents the dominant yellow-fur allele and a represents the recessive black-fur allele. We the black furred dog has to be genotype aa because he displays the recessive phenotype. The offspring produced from this cross would be 2 Aa and 2 aa genotypes, based on a punnet square.

This cross would generate offspring that are 50% Aa and 50% aa. This corresponds to 50% yellow and 50% black.

First, we need to find the genotype of the man. We know that his father has the disease, and that his mother is homozygous dominant. For his father to display the autosomal recessive trait, he must be homozygous recessive. We can thus write the man's parents' genotypes, using A as the dominant allele and a as the recessive allele.

Parents: AA (mother) x aa (father)

Offspring: All offspring will be Aa.

The man must inherit one allele from each parent, meaning he must be heterozygous.

This man, we are told, marries a heterozygous woman and they have a child. Again, we can write out this cross.

Man and woman: Aa (man) x Aa (woman)

Offspring: 1 AA (dominant), 2 Aa (dominant), 1 aa (recessive)

The possible offspring from this cross show a three-to-one ratio for displaying the dominant phenotype. Only one of the four possible offspring will be homozygous recessive and display the recessive phenotype. This one-in-four chance correspond to a 25% chance.

We know that the allele is autosomal, the father is heterozygous and black, and the mother is homozygous and white. From this information, we can determine that black must be dominant to white since the heterozygote shows the black phenotype. We will use B to represent the dominant black allele and b to represent the recessive white allele.

Cross: Bb x bb

Offspring: Half Bb (black) and half bb (white)

We can see that roughly half of the offspring will show the white phenotype. If there are twelve offspring, six of them will be white.

Alleles are simply different versions of the same gene that encode for variations of the same characteristic. For example, different eye colors are encoded by different alleles of the same gene.

When a homozygous tall pea plant and a homozygous short pea plant are crossed, the next generation are all heterozygous and the dominant allele is expressed in all the plants, and the recessive trait seems to disappear. Since we are not told whether the tall or short allele is dominant, we cannot assume either.