Michaelis-Menten Graphs - Biochemistry
Card 1 of 20
In a Lineweaver-Burk plot, the slope is .
In a Lineweaver-Burk plot, the slope is .
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A Lineweaver-Burk is a double-reciprocal of the Michaelis-Menten equation. The equation for the graph, in 
form is:
From this graph, we can see that the slope is 
.
A Lineweaver-Burk is a double-reciprocal of the Michaelis-Menten equation. The equation for the graph, in
From this graph, we can see that the slope is
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Where on a Michaelis-Menten graph is the slope of reaction velocity linear?
Where on a Michaelis-Menten graph is the slope of reaction velocity linear?
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When substrate concentration is high, all of the active sites can be constantly occupied by enzyme. Further, the active sites can be saturated by enzyme when concentration is very high. But, when the concentration of substrate is low, the reaction velocity is considered to be linear.
When substrate concentration is high, all of the active sites can be constantly occupied by enzyme. Further, the active sites can be saturated by enzyme when concentration is very high. But, when the concentration of substrate is low, the reaction velocity is considered to be linear.
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In a Michaelis-Menten plot of enzyme kinetics, the reaction rate is plotted as a function of substrate concentration. Why is it that as substrate concentration increases, the curve of the graph levels off and reaches a plateau?
In a Michaelis-Menten plot of enzyme kinetics, the reaction rate is plotted as a function of substrate concentration. Why is it that as substrate concentration increases, the curve of the graph levels off and reaches a plateau?
Tap to reveal answer
In a classic Michaelis-Menten graph, the y-axis represents reaction rate and the x-axis represents substrate concentration. At low substrate concentrations, the reaction rate increases sharply. But as the substrate concentration climbs, the reaction rate begins to increase less and less until it comes to a point where it plateaus into a flat line.
The reason this happens is because the enzyme becomes saturated with substrate. When substrate concentration is low, many of the enzymes in solution aren't doing anything, so they're readily available to convert substrate into product. Thus, adding even just a little bit of substrate will result in a dramatically increased reaction rate. When a high concentration of substrate is present, all of the enzymes in solution are busy. In other words, as soon as an enzyme converts a substrate into product, it immediately becomes occupied with another substrate. Since this process can't occur any faster unless more enzymes are added, all of the other substrate in solution have to wait their turn. Thus, any increase in substrate concentration under these circumstances results in very little, if any, increase in reaction rate.
In a classic Michaelis-Menten graph, the y-axis represents reaction rate and the x-axis represents substrate concentration. At low substrate concentrations, the reaction rate increases sharply. But as the substrate concentration climbs, the reaction rate begins to increase less and less until it comes to a point where it plateaus into a flat line.
The reason this happens is because the enzyme becomes saturated with substrate. When substrate concentration is low, many of the enzymes in solution aren't doing anything, so they're readily available to convert substrate into product. Thus, adding even just a little bit of substrate will result in a dramatically increased reaction rate. When a high concentration of substrate is present, all of the enzymes in solution are busy. In other words, as soon as an enzyme converts a substrate into product, it immediately becomes occupied with another substrate. Since this process can't occur any faster unless more enzymes are added, all of the other substrate in solution have to wait their turn. Thus, any increase in substrate concentration under these circumstances results in very little, if any, increase in reaction rate.
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On a Lineweaver-Burk plot, which of the following is correct?
On a Lineweaver-Burk plot, which of the following is correct?
Tap to reveal answer
On a Lineweaver-Burk plot, the following are the correct matches regarding points of importance?
X-axis = 
Y-axis = 
X-intercept = 
Y-intercept = 
Slope = 
On a Lineweaver-Burk plot, the following are the correct matches regarding points of importance?
X-axis =
Y-axis =
X-intercept =
Y-intercept =
Slope =
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In the presence of a competitive inhibitor, which of the following changes will always be observed on the Lineweaver-Burk plot?
In the presence of a competitive inhibitor, which of the following changes will always be observed on the Lineweaver-Burk plot?
Tap to reveal answer
will remain the same for an inhibited enzyme when a competitive inhibitor is used. With this information, one can figure out what will happen to the line for an inhibited enzyme on a Lineweaver Burk plot. The y-intercept represents 
on these graphs, and so in the presence of a competitive inhibitor, the y-intercept will remain unchanged for an inhibited enzyme. The x-intercept represents 
. A competitive inhibitor will raise 
, and so the inhibited enzyme's x-intercept will be closer to the origin.
← Didn't Know|Knew It →
In a Lineweaver-Burk plot, the slope is .
In a Lineweaver-Burk plot, the slope is .
Tap to reveal answer
A Lineweaver-Burk is a double-reciprocal of the Michaelis-Menten equation. The equation for the graph, in form is:
From this graph, we can see that the slope is .
A Lineweaver-Burk is a double-reciprocal of the Michaelis-Menten equation. The equation for the graph, in
From this graph, we can see that the slope is
← Didn't Know|Knew It →
Where on a Michaelis-Menten graph is the slope of reaction velocity linear?
Where on a Michaelis-Menten graph is the slope of reaction velocity linear?
Tap to reveal answer
When substrate concentration is high, all of the active sites can be constantly occupied by enzyme. Further, the active sites can be saturated by enzyme when concentration is very high. But, when the concentration of substrate is low, the reaction velocity is considered to be linear.
When substrate concentration is high, all of the active sites can be constantly occupied by enzyme. Further, the active sites can be saturated by enzyme when concentration is very high. But, when the concentration of substrate is low, the reaction velocity is considered to be linear.
← Didn't Know|Knew It →
In a Michaelis-Menten plot of enzyme kinetics, the reaction rate is plotted as a function of substrate concentration. Why is it that as substrate concentration increases, the curve of the graph levels off and reaches a plateau?
In a Michaelis-Menten plot of enzyme kinetics, the reaction rate is plotted as a function of substrate concentration. Why is it that as substrate concentration increases, the curve of the graph levels off and reaches a plateau?
Tap to reveal answer
In a classic Michaelis-Menten graph, the y-axis represents reaction rate and the x-axis represents substrate concentration. At low substrate concentrations, the reaction rate increases sharply. But as the substrate concentration climbs, the reaction rate begins to increase less and less until it comes to a point where it plateaus into a flat line.
The reason this happens is because the enzyme becomes saturated with substrate. When substrate concentration is low, many of the enzymes in solution aren't doing anything, so they're readily available to convert substrate into product. Thus, adding even just a little bit of substrate will result in a dramatically increased reaction rate. When a high concentration of substrate is present, all of the enzymes in solution are busy. In other words, as soon as an enzyme converts a substrate into product, it immediately becomes occupied with another substrate. Since this process can't occur any faster unless more enzymes are added, all of the other substrate in solution have to wait their turn. Thus, any increase in substrate concentration under these circumstances results in very little, if any, increase in reaction rate.
In a classic Michaelis-Menten graph, the y-axis represents reaction rate and the x-axis represents substrate concentration. At low substrate concentrations, the reaction rate increases sharply. But as the substrate concentration climbs, the reaction rate begins to increase less and less until it comes to a point where it plateaus into a flat line.
The reason this happens is because the enzyme becomes saturated with substrate. When substrate concentration is low, many of the enzymes in solution aren't doing anything, so they're readily available to convert substrate into product. Thus, adding even just a little bit of substrate will result in a dramatically increased reaction rate. When a high concentration of substrate is present, all of the enzymes in solution are busy. In other words, as soon as an enzyme converts a substrate into product, it immediately becomes occupied with another substrate. Since this process can't occur any faster unless more enzymes are added, all of the other substrate in solution have to wait their turn. Thus, any increase in substrate concentration under these circumstances results in very little, if any, increase in reaction rate.
← Didn't Know|Knew It →
On a Lineweaver-Burk plot, which of the following is correct?
On a Lineweaver-Burk plot, which of the following is correct?
Tap to reveal answer
On a Lineweaver-Burk plot, the following are the correct matches regarding points of importance?
X-axis =
Y-axis =
X-intercept =
Y-intercept =
Slope =
On a Lineweaver-Burk plot, the following are the correct matches regarding points of importance?
X-axis =
Y-axis =
X-intercept =
Y-intercept =
Slope =
← Didn't Know|Knew It →
In the presence of a competitive inhibitor, which of the following changes will always be observed on the Lineweaver-Burk plot?
In the presence of a competitive inhibitor, which of the following changes will always be observed on the Lineweaver-Burk plot?
Tap to reveal answer
will remain the same for an inhibited enzyme when a competitive inhibitor is used. With this information, one can figure out what will happen to the line for an inhibited enzyme on a Lineweaver Burk plot. The y-intercept represents on these graphs, and so in the presence of a competitive inhibitor, the y-intercept will remain unchanged for an inhibited enzyme. The x-intercept represents . A competitive inhibitor will raise , and so the inhibited enzyme's x-intercept will be closer to the origin.
← Didn't Know|Knew It →
Where on a Michaelis-Menten graph is the slope of reaction velocity linear?
Where on a Michaelis-Menten graph is the slope of reaction velocity linear?
Tap to reveal answer
When substrate concentration is high, all of the active sites can be constantly occupied by enzyme. Further, the active sites can be saturated by enzyme when concentration is very high. But, when the concentration of substrate is low, the reaction velocity is considered to be linear.
When substrate concentration is high, all of the active sites can be constantly occupied by enzyme. Further, the active sites can be saturated by enzyme when concentration is very high. But, when the concentration of substrate is low, the reaction velocity is considered to be linear.
← Didn't Know|Knew It →
In a Lineweaver-Burk plot, the slope is .
In a Lineweaver-Burk plot, the slope is .
Tap to reveal answer
A Lineweaver-Burk is a double-reciprocal of the Michaelis-Menten equation. The equation for the graph, in form is:
From this graph, we can see that the slope is .
A Lineweaver-Burk is a double-reciprocal of the Michaelis-Menten equation. The equation for the graph, in
From this graph, we can see that the slope is
← Didn't Know|Knew It →
In a Michaelis-Menten plot of enzyme kinetics, the reaction rate is plotted as a function of substrate concentration. Why is it that as substrate concentration increases, the curve of the graph levels off and reaches a plateau?
In a Michaelis-Menten plot of enzyme kinetics, the reaction rate is plotted as a function of substrate concentration. Why is it that as substrate concentration increases, the curve of the graph levels off and reaches a plateau?
Tap to reveal answer
In a classic Michaelis-Menten graph, the y-axis represents reaction rate and the x-axis represents substrate concentration. At low substrate concentrations, the reaction rate increases sharply. But as the substrate concentration climbs, the reaction rate begins to increase less and less until it comes to a point where it plateaus into a flat line.
The reason this happens is because the enzyme becomes saturated with substrate. When substrate concentration is low, many of the enzymes in solution aren't doing anything, so they're readily available to convert substrate into product. Thus, adding even just a little bit of substrate will result in a dramatically increased reaction rate. When a high concentration of substrate is present, all of the enzymes in solution are busy. In other words, as soon as an enzyme converts a substrate into product, it immediately becomes occupied with another substrate. Since this process can't occur any faster unless more enzymes are added, all of the other substrate in solution have to wait their turn. Thus, any increase in substrate concentration under these circumstances results in very little, if any, increase in reaction rate.
In a classic Michaelis-Menten graph, the y-axis represents reaction rate and the x-axis represents substrate concentration. At low substrate concentrations, the reaction rate increases sharply. But as the substrate concentration climbs, the reaction rate begins to increase less and less until it comes to a point where it plateaus into a flat line.
The reason this happens is because the enzyme becomes saturated with substrate. When substrate concentration is low, many of the enzymes in solution aren't doing anything, so they're readily available to convert substrate into product. Thus, adding even just a little bit of substrate will result in a dramatically increased reaction rate. When a high concentration of substrate is present, all of the enzymes in solution are busy. In other words, as soon as an enzyme converts a substrate into product, it immediately becomes occupied with another substrate. Since this process can't occur any faster unless more enzymes are added, all of the other substrate in solution have to wait their turn. Thus, any increase in substrate concentration under these circumstances results in very little, if any, increase in reaction rate.
← Didn't Know|Knew It →
On a Lineweaver-Burk plot, which of the following is correct?
On a Lineweaver-Burk plot, which of the following is correct?
Tap to reveal answer
On a Lineweaver-Burk plot, the following are the correct matches regarding points of importance?
X-axis =
Y-axis =
X-intercept =
Y-intercept =
Slope =
On a Lineweaver-Burk plot, the following are the correct matches regarding points of importance?
X-axis =
Y-axis =
X-intercept =
Y-intercept =
Slope =
← Didn't Know|Knew It →
In the presence of a competitive inhibitor, which of the following changes will always be observed on the Lineweaver-Burk plot?
In the presence of a competitive inhibitor, which of the following changes will always be observed on the Lineweaver-Burk plot?
Tap to reveal answer
will remain the same for an inhibited enzyme when a competitive inhibitor is used. With this information, one can figure out what will happen to the line for an inhibited enzyme on a Lineweaver Burk plot. The y-intercept represents on these graphs, and so in the presence of a competitive inhibitor, the y-intercept will remain unchanged for an inhibited enzyme. The x-intercept represents . A competitive inhibitor will raise , and so the inhibited enzyme's x-intercept will be closer to the origin.
← Didn't Know|Knew It →
Where on a Michaelis-Menten graph is the slope of reaction velocity linear?
Where on a Michaelis-Menten graph is the slope of reaction velocity linear?
Tap to reveal answer
When substrate concentration is high, all of the active sites can be constantly occupied by enzyme. Further, the active sites can be saturated by enzyme when concentration is very high. But, when the concentration of substrate is low, the reaction velocity is considered to be linear.
When substrate concentration is high, all of the active sites can be constantly occupied by enzyme. Further, the active sites can be saturated by enzyme when concentration is very high. But, when the concentration of substrate is low, the reaction velocity is considered to be linear.
← Didn't Know|Knew It →
In a Lineweaver-Burk plot, the slope is .
In a Lineweaver-Burk plot, the slope is .
Tap to reveal answer
A Lineweaver-Burk is a double-reciprocal of the Michaelis-Menten equation. The equation for the graph, in form is:
From this graph, we can see that the slope is .
A Lineweaver-Burk is a double-reciprocal of the Michaelis-Menten equation. The equation for the graph, in
From this graph, we can see that the slope is
← Didn't Know|Knew It →
In a Michaelis-Menten plot of enzyme kinetics, the reaction rate is plotted as a function of substrate concentration. Why is it that as substrate concentration increases, the curve of the graph levels off and reaches a plateau?
In a Michaelis-Menten plot of enzyme kinetics, the reaction rate is plotted as a function of substrate concentration. Why is it that as substrate concentration increases, the curve of the graph levels off and reaches a plateau?
Tap to reveal answer
In a classic Michaelis-Menten graph, the y-axis represents reaction rate and the x-axis represents substrate concentration. At low substrate concentrations, the reaction rate increases sharply. But as the substrate concentration climbs, the reaction rate begins to increase less and less until it comes to a point where it plateaus into a flat line.
The reason this happens is because the enzyme becomes saturated with substrate. When substrate concentration is low, many of the enzymes in solution aren't doing anything, so they're readily available to convert substrate into product. Thus, adding even just a little bit of substrate will result in a dramatically increased reaction rate. When a high concentration of substrate is present, all of the enzymes in solution are busy. In other words, as soon as an enzyme converts a substrate into product, it immediately becomes occupied with another substrate. Since this process can't occur any faster unless more enzymes are added, all of the other substrate in solution have to wait their turn. Thus, any increase in substrate concentration under these circumstances results in very little, if any, increase in reaction rate.
In a classic Michaelis-Menten graph, the y-axis represents reaction rate and the x-axis represents substrate concentration. At low substrate concentrations, the reaction rate increases sharply. But as the substrate concentration climbs, the reaction rate begins to increase less and less until it comes to a point where it plateaus into a flat line.
The reason this happens is because the enzyme becomes saturated with substrate. When substrate concentration is low, many of the enzymes in solution aren't doing anything, so they're readily available to convert substrate into product. Thus, adding even just a little bit of substrate will result in a dramatically increased reaction rate. When a high concentration of substrate is present, all of the enzymes in solution are busy. In other words, as soon as an enzyme converts a substrate into product, it immediately becomes occupied with another substrate. Since this process can't occur any faster unless more enzymes are added, all of the other substrate in solution have to wait their turn. Thus, any increase in substrate concentration under these circumstances results in very little, if any, increase in reaction rate.
← Didn't Know|Knew It →
On a Lineweaver-Burk plot, which of the following is correct?
On a Lineweaver-Burk plot, which of the following is correct?
Tap to reveal answer
On a Lineweaver-Burk plot, the following are the correct matches regarding points of importance?
X-axis =
Y-axis =
X-intercept =
Y-intercept =
Slope =
On a Lineweaver-Burk plot, the following are the correct matches regarding points of importance?
X-axis =
Y-axis =
X-intercept =
Y-intercept =
Slope =
← Didn't Know|Knew It →
In the presence of a competitive inhibitor, which of the following changes will always be observed on the Lineweaver-Burk plot?
In the presence of a competitive inhibitor, which of the following changes will always be observed on the Lineweaver-Burk plot?
Tap to reveal answer
will remain the same for an inhibited enzyme when a competitive inhibitor is used. With this information, one can figure out what will happen to the line for an inhibited enzyme on a Lineweaver Burk plot. The y-intercept represents on these graphs, and so in the presence of a competitive inhibitor, the y-intercept will remain unchanged for an inhibited enzyme. The x-intercept represents . A competitive inhibitor will raise , and so the inhibited enzyme's x-intercept will be closer to the origin.
← Didn't Know|Knew It →