Knowing How and When to Subtract

1st Grade Math · Learn by Concept

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1st Grade Math › Knowing How and When to Subtract

1 - 10

1

$\frac{\begin{array}[b]{r}15\ -\ 11\end{array}}{ \ \ \ \space ?}$

CORRECT

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Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}15\ -\ 11\end{array}}{ \ \ \ \ \ \space 4}$

2

$\frac{\begin{array}[b]{r}18\ -\ 3\end{array}}{ \ \ \ \space ?}$

CORRECT

0

0

0

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Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}18\ -\ 3\end{array}}{ \ \ \space15}$

3

$\frac{\begin{array}[b]{r}9\ -\ 7\end{array}}{ \ \ \ \space ?}$

CORRECT

0

0

0

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Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}9\ -\ 7\end{array}}{ \ \ \ \space 2}$

4

$\frac{\begin{array}[b]{r}14\ -\ 10\end{array}}{ \ \ \ \space ?}$

CORRECT

0

0

0

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Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}14\ -\ 10\end{array}}{ \ \ \ \ \ \space 4}$

5

$\frac{\begin{array}[b]{r}4\ -\ 2\end{array}}{ \ \ \ \space ?}$

CORRECT

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0

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Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}4\ -\ 2\end{array}}{ \ \ \ \space 2}$

6

$\frac{\begin{array}[b]{r}8\ -\ 5\end{array}}{ \ \ \ \space ?}$

CORRECT

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0

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Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}8\ -\ 5\end{array}}{ \ \ \ \space 3}$

7

$\frac{\begin{array}[b]{r}12\ -\ 5\end{array}}{ \ \ \ \space ?}$

CORRECT

0

0

0

0

Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}12\ -\ 5\end{array}}{ \ \ \ \space 7}$

8

$\frac{\begin{array}[b]{r}19\ -\ 6\end{array}}{ \ \ \ \space ?}$

CORRECT

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0

0

0

Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}19\ -\ 6\end{array}}{ \ \ \space 13}$

9

$\frac{\begin{array}[b]{r}10\ -\ 3\end{array}}{ \ \ \ \space ?}$

CORRECT

0

0

0

0

Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}10\ -\ 3\end{array}}{ \ \ \ \space 7}$

10

$\frac{\begin{array}[b]{r}11\ -\ 6\end{array}}{ \ \ \ \space ?}$

CORRECT

0

0

0

0

Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}11\ -\ 6\end{array}}{ \ \ \ \space 5}$

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