Range - GRE Quantitative Reasoning

The standard deviation tells us how much variation, or dispersion, there is on average between the numbers in a set and their mean. Therefore Quantity B is greater, because Set B has a larger standard deviation than Set A.

The first step of this problem should be to reorder Set Q into numerical order:

The range of a set is the largest value minus the lowest value, so for this set, the range is

The median of a set depends on whether or not there is an even or odd amount of numbers in the set. For a set with values:

Odd:

Even:

Since there is an even number of numbers in this set, the median is

The two quantities are equal.

The range is the difference between the largest and smallest numbers of a set. The biggest number is 15 and the smallest is 1, so our range is 15 – 1 = 14.

The standard deviation tells us how much variation, or dispersion, there is on average between the numbers in a set and their mean. Therefore Quantity B is greater, because Set B has a larger standard deviation than Set A.

The first step of this problem should be to reorder Set Q into numerical order:

The range of a set is the largest value minus the lowest value, so for this set, the range is

The median of a set depends on whether or not there is an even or odd amount of numbers in the set. For a set with values:

Odd:

Even:

Since there is an even number of numbers in this set, the median is

The two quantities are equal.

The range is the difference between the largest and smallest numbers of a set. The biggest number is 15 and the smallest is 1, so our range is 15 – 1 = 14.

The standard deviation tells us how much variation, or dispersion, there is on average between the numbers in a set and their mean. Therefore Quantity B is greater, because Set B has a larger standard deviation than Set A.

The first step of this problem should be to reorder Set Q into numerical order:

The range of a set is the largest value minus the lowest value, so for this set, the range is

The median of a set depends on whether or not there is an even or odd amount of numbers in the set. For a set with values:

Odd:

Even:

Since there is an even number of numbers in this set, the median is

The two quantities are equal.

The median is the middle value in a set of numbers, and the mode is the number that occurs.

In Column A, the median is 6 and the mode is 6, so the sum of the median and the mode of Set G is 12.

The range is the difference between the highest and lowest numbers of the set.

In Column B, the range is 12 – 2 = 10.

Column A is greater than Column B.

The range is the difference between the largest and smallest numbers of a set. The biggest number is 15 and the smallest is 1, so our range is 15 – 1 = 14.

The standard deviation tells us how much variation, or dispersion, there is on average between the numbers in a set and their mean. Therefore Quantity B is greater, because Set B has a larger standard deviation than Set A.

The first step of this problem should be to reorder Set Q into numerical order:

The range of a set is the largest value minus the lowest value, so for this set, the range is

The median of a set depends on whether or not there is an even or odd amount of numbers in the set. For a set with values:

Odd:

Even:

Since there is an even number of numbers in this set, the median is

The two quantities are equal.

The median is the middle value in a set of numbers, and the mode is the number that occurs.

In Column A, the median is 6 and the mode is 6, so the sum of the median and the mode of Set G is 12.

The range is the difference between the highest and lowest numbers of the set.

In Column B, the range is 12 – 2 = 10.

Column A is greater than Column B.

The range is the difference between the largest and smallest numbers of a set. The biggest number is 15 and the smallest is 1, so our range is 15 – 1 = 14.

The standard deviation tells us how much variation, or dispersion, there is on average between the numbers in a set and their mean. Therefore Quantity B is greater, because Set B has a larger standard deviation than Set A.

The first step of this problem should be to reorder Set Q into numerical order:

The range of a set is the largest value minus the lowest value, so for this set, the range is

The median of a set depends on whether or not there is an even or odd amount of numbers in the set. For a set with values:

Odd:

Even:

Since there is an even number of numbers in this set, the median is

The two quantities are equal.

The standard deviation tells us how much variation, or dispersion, there is on average between the numbers in a set and their mean. Therefore Quantity B is greater, because Set B has a larger standard deviation than Set A.

The median is the middle value in a set of numbers, and the mode is the number that occurs.

In Column A, the median is 6 and the mode is 6, so the sum of the median and the mode of Set G is 12.

The range is the difference between the highest and lowest numbers of the set.

In Column B, the range is 12 – 2 = 10.

Column A is greater than Column B.

The range is the difference between the largest and smallest numbers of a set. The biggest number is 15 and the smallest is 1, so our range is 15 – 1 = 14.