Whole and Part - ISEE Middle Level Quantitative Reasoning

If the store sells the dress for 40% off, that means it is worth 60% of its original price.

Therefore, if you multiply 60% times the original price of the dress, you will know what the current price of the dress is.

To do this, first divide your percentage by 100.

Then, multiply the result of this times the original price of the dress.

The new result is your answer.

In order to figure out what 60% of 120 is, multiply 60% by 120. To do this, first divide your percentage by 100.

Then, multiply the result times 120.

The new result is your answer.

If the clothing store discounts an already discounted price, it means that we are trying to find a percentage of an already smaller part of the original number. First, if the original discount was 25%, that means that the shirt was sold for 75% the original price the first week.

So, we must first figure out what the shirt was worth at 75% the original price. To do this, divide the percentage by 100.

Multiply the result times the original price of the shirt.

This is the price of the shirt after the first discount. This new price is then discounted by another 20%. So, the newest price will be 80% of the value of the first discount.

To find out what the price is after this is done, multiply the percentage by the new price. So, first divide the percentage by 100.

Multiply this result by the discounted price.

The result is your answer.

The question asks you to find 75% of a smaller part of 48. In order to figure this out, you must first figure out what the value of the smaller part is. To figure out what 25% of 48 is, multiply 48 by 25%. First, divide the percentage by 100.

Then, multiply 48 by the result.

The second part of the question asks you to figure out what 75% of this new number is. Just like before, first divide the percentage by 100.

Then, multiply the result times 12.

The result is the answer.

To figure out what 18% of any number is, first divide the percentage by 100.

Then, multiply this result times the original number.

The result is your answer.

To figure out what 18% of any number is, first divide the percentage by 100.

Then, multiply this result times the original number.

The result is the tip. To figure out the total amount paid, add the tip to the original price of the bill.

The question asks you to figure out what 50% more than a smaller part of 40 is. To do this, you must first solve what 15% of 40 is. First, divide the percentage by 100.

Then, multiply the result times 40.

You then must figure out what 50% more than this new number is. 50% more is equal to 150% of the original value. Just like before, divide this percentage by 100.

Then, multiply the result times 6.

This result is your answer.

The question asks you to figure out what 20% more than a smaller amount of 40 is. To do this, you must first solve for the smaller amount. So, first divide 40 by 2 since it asks for half of 40.

Since 20% than a number is equal to 120% of the original value of that number, multiply 20 by 120%. To do this, first divide the percentage by 100.

Then, multiply the result times 20.

This result is your answer.

To figure out what a percentage of a particular number is, first divide that percentage by 100.

Then, multiply the result times the original number.

This result is your answer.

The easiest way to find 42 percent of 5 is to first find 42 percent of 10.

42 percent of 10 can be calculated by multiplying .42 by 10. This results in 4.2.

Given that 5 is half of 10, it follows that 42 percent of 5 is equal to half of 4.2.

Half of 4.2 is equal to 2.1, which is the correct answer.

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.