Graphing Exponential Functions - Math

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Question

Find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ .

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Answer

To find the -intercept, set in the equation and solve.

$y=\frac{x^3+2x+8}{x^2-36}$

$y=\frac{(0)^3+2(0)+8}{(0)^2-36}$

$y=\frac{(0)+(0)+8}{(0)-36}$

$y=\frac{8}{-36}$

$y=-\frac{2}{9}$

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Question

Find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ , we need to set the numerator equal to zero.

That means .

The best way to solve for a funky equation like this is to graph it in your calculator and calculate the roots. The result is $x\approx -1.67$ .

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Question

Find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ , we need to set the numerator equal to zero and solve.

First, notice that can be factored into . Now set that equal to zero: .

Since we have two sets in parentheses, there are two separate values that can cause our equation to equal zero: one where and one where .

Solve for each value:

and

.

Therefore there are two -interecpts: and .

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ , set the value equal to zero and solve.

$y=\frac{x^2+9x+8}{x^2-44}$

$y=\frac{(0)^2+9(0)+8}{(0)^2-44}$

$y=\frac{(0)+(0)+8}{(0)-44}$

$y=\frac{8}{-44}$

$y=-\frac{2}{11}$

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ .

Tap to reveal answer

Answer

To find the -intercept, set in the equation and solve.

$y=\frac{x^3+2x+8}{x^2-36}$

$y=\frac{(0)^3+2(0)+8}{(0)^2-36}$

$y=\frac{(0)+(0)+8}{(0)-36}$

$y=\frac{8}{-36}$

$y=-\frac{2}{9}$

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ , we need to set the numerator equal to zero.

That means .

The best way to solve for a funky equation like this is to graph it in your calculator and calculate the roots. The result is $x\approx -1.67$ .

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ , we need to set the numerator equal to zero and solve.

First, notice that can be factored into . Now set that equal to zero: .

Since we have two sets in parentheses, there are two separate values that can cause our equation to equal zero: one where and one where .

Solve for each value:

and

.

Therefore there are two -interecpts: and .

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ , set the value equal to zero and solve.

$y=\frac{x^2+9x+8}{x^2-44}$

$y=\frac{(0)^2+9(0)+8}{(0)^2-44}$

$y=\frac{(0)+(0)+8}{(0)-44}$

$y=\frac{8}{-44}$

$y=-\frac{2}{11}$

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ .

Tap to reveal answer

Answer

To find the -intercept, set in the equation and solve.

$y=\frac{x^3+2x+8}{x^2-36}$

$y=\frac{(0)^3+2(0)+8}{(0)^2-36}$

$y=\frac{(0)+(0)+8}{(0)-36}$

$y=\frac{8}{-36}$

$y=-\frac{2}{9}$

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ , we need to set the numerator equal to zero.

That means .

The best way to solve for a funky equation like this is to graph it in your calculator and calculate the roots. The result is $x\approx -1.67$ .

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ , we need to set the numerator equal to zero and solve.

First, notice that can be factored into . Now set that equal to zero: .

Since we have two sets in parentheses, there are two separate values that can cause our equation to equal zero: one where and one where .

Solve for each value:

and

.

Therefore there are two -interecpts: and .

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ , set the value equal to zero and solve.

$y=\frac{x^2+9x+8}{x^2-44}$

$y=\frac{(0)^2+9(0)+8}{(0)^2-44}$

$y=\frac{(0)+(0)+8}{(0)-44}$

$y=\frac{8}{-44}$

$y=-\frac{2}{11}$

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ .

Tap to reveal answer

Answer

To find the -intercept, set in the equation and solve.

$y=\frac{x^3+2x+8}{x^2-36}$

$y=\frac{(0)^3+2(0)+8}{(0)^2-36}$

$y=\frac{(0)+(0)+8}{(0)-36}$

$y=\frac{8}{-36}$

$y=-\frac{2}{9}$

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^3+2x+8}{x^2-36}$ , we need to set the numerator equal to zero.

That means .

The best way to solve for a funky equation like this is to graph it in your calculator and calculate the roots. The result is $x\approx -1.67$ .

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ , we need to set the numerator equal to zero and solve.

First, notice that can be factored into . Now set that equal to zero: .

Since we have two sets in parentheses, there are two separate values that can cause our equation to equal zero: one where and one where .

Solve for each value:

and

.

Therefore there are two -interecpts: and .

← Didn't Know|Knew It →

Question

Find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ .

Tap to reveal answer

Answer

To find the -intercept(s) of $y=\frac{x^2+9x+8}{x^2-44}$ , set the value equal to zero and solve.

$y=\frac{x^2+9x+8}{x^2-44}$

$y=\frac{(0)^2+9(0)+8}{(0)^2-44}$

$y=\frac{(0)+(0)+8}{(0)-44}$

$y=\frac{8}{-44}$

$y=-\frac{2}{11}$

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