Polynomials - Math
Card 1 of 136
Factor the polynomial completely and solve for
.

Factor the polynomial completely and solve for .
Tap to reveal answer
To factor and solve for
in the equation 
Factor
out of the equation

Use the "difference of squares" technique to factor the parenthetical term, which provides the completely factored equation:

Any value that causes any one of the three terms
,
, and
to be
will be a solution to the equation, therefore

To factor and solve for in the equation
Factor out of the equation
Use the "difference of squares" technique to factor the parenthetical term, which provides the completely factored equation:
Any value that causes any one of the three terms ,
, and
to be
will be a solution to the equation, therefore
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Factor the polynomial completely and solve for
.

Factor the polynomial completely and solve for .
Tap to reveal answer
To factor and solve for
in the equation 
Factor
out of the equation

Use the "difference of squares" technique to factor the parenthetical term, which provides the completely factored equation:

Any value that causes any one of the three terms
,
, and
to be
will be a solution to the equation, therefore

To factor and solve for in the equation
Factor out of the equation
Use the "difference of squares" technique to factor the parenthetical term, which provides the completely factored equation:
Any value that causes any one of the three terms ,
, and
to be
will be a solution to the equation, therefore
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Factor the polynomial completely and solve for
.

Factor the polynomial completely and solve for .
Tap to reveal answer
To factor and solve for
in the equation 
Factor
out of the equation

Use the "difference of squares" technique to factor the parenthetical term, which provides the completely factored equation:

Any value that causes any one of the three terms
,
, and
to be
will be a solution to the equation, therefore

To factor and solve for in the equation
Factor out of the equation
Use the "difference of squares" technique to factor the parenthetical term, which provides the completely factored equation:
Any value that causes any one of the three terms ,
, and
to be
will be a solution to the equation, therefore
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Factor the polynomial completely and solve for
.

Factor the polynomial completely and solve for .
Tap to reveal answer
To factor and solve for
in the equation 
Factor
out of the equation

Use the "difference of squares" technique to factor the parenthetical term, which provides the completely factored equation:

Any value that causes any one of the three terms
,
, and
to be
will be a solution to the equation, therefore

To factor and solve for in the equation
Factor out of the equation
Use the "difference of squares" technique to factor the parenthetical term, which provides the completely factored equation:
Any value that causes any one of the three terms ,
, and
to be
will be a solution to the equation, therefore
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Factor the following expression:

Factor the following expression:
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You can see that each term in the equation has an "x", therefore by factoring "x" from each term you can get that the equation equals
.
You can see that each term in the equation has an "x", therefore by factoring "x" from each term you can get that the equation equals .
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Expand this expression:


Expand this expression:
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Use the FOIL method (First, Outer, Inner, Last):




Put all of these terms together:

Combine like terms:

Use the FOIL method (First, Outer, Inner, Last):
Put all of these terms together:
Combine like terms:
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Find the zeros.

Find the zeros.
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This is a difference of perfect cubes so it factors to
. Only the first expression will yield an answer when set equal to 0, which is 1. The second expression will never cross the
-axis. Therefore, your answer is only 1.
This is a difference of perfect cubes so it factors to . Only the first expression will yield an answer when set equal to 0, which is 1. The second expression will never cross the
-axis. Therefore, your answer is only 1.
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Find the zeros.

Find the zeros.
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Factor the equation to
. Set
and get one of your
's to be
. Then factor the second expression to
. Set them equal to zero and you get
.
Factor the equation to . Set
and get one of your
's to be
. Then factor the second expression to
. Set them equal to zero and you get
.
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Factor 
Factor
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Use the difference of perfect cubes equation:

In
,
and ![b=\sqrt[3]{64}=4](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/94643/gif.latex)


Use the difference of perfect cubes equation:
In ,
and
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Factor this expression:

Factor this expression:
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First consider all the factors of 12:
1 and 12
2 and 6
3 and 4
Then consider which of these pairs adds up to 7. This pair is 3 and 4.
Therefore the answer is
.
First consider all the factors of 12:
1 and 12
2 and 6
3 and 4
Then consider which of these pairs adds up to 7. This pair is 3 and 4.
Therefore the answer is .
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Factor the following polynomial:

Factor the following polynomial:
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Begin by extracting
from the polynomial:


Now, factor the remainder of the polynomial as a difference of cubes:

Begin by extracting from the polynomial:
Now, factor the remainder of the polynomial as a difference of cubes:
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Factor the following polynomial:

Factor the following polynomial:
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Begin by rearranging like terms:


Now, factor out like terms:

Rearrange the polynomial:

Begin by rearranging like terms:
Now, factor out like terms:
Rearrange the polynomial:
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Factor the following polynomial:

Factor the following polynomial:
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Begin by rearranging like terms:


Now, factor out like terms:

Rearrange the polynomial:

Factor:


Begin by rearranging like terms:
Now, factor out like terms:
Rearrange the polynomial:
Factor:
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Factor the following polynomial:

Factor the following polynomial:
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Begin by separating
into like terms. You do this by multiplying
and
, then finding factors which sum to 


Now, extract like terms:

Simplify:

Begin by separating into like terms. You do this by multiplying
and
, then finding factors which sum to
Now, extract like terms:
Simplify:
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Factor the following polynomial:

Factor the following polynomial:
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To begin, distribute the squares:

![[(3a-4b)+(a+3b)][(3a-4b)-(a+3b)]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/153192/gif.latex)
Now, combine like terms:

To begin, distribute the squares:
Now, combine like terms:
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Factor the following polynomial:

Factor the following polynomial:
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Begin by extracting
from the polynomial:


Now, distribute the cubic polynomial:

Begin by extracting from the polynomial:
Now, distribute the cubic polynomial:
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Factor the following polynomial:

Factor the following polynomial:
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Begin by extracting like terms:


Now, rearrange the right side of the polynomial by reversing the signs:

Combine like terms:

Factor the square and cubic polynomial:

Begin by extracting like terms:
Now, rearrange the right side of the polynomial by reversing the signs:
Combine like terms:
Factor the square and cubic polynomial:
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Factor the following polynomial:

Factor the following polynomial:
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Begin by rearranging the terms to group together the quadratic:


Now, convert the quadratic into a square:

Finally, distribute the
:

Begin by rearranging the terms to group together the quadratic:
Now, convert the quadratic into a square:
Finally, distribute the :
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Factor the following polynomial:

Factor the following polynomial:
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Begin by extracting
from the polynomial:


Now, rearrange to combine like terms:

Extract the like terms and factor the cubic:
![mn[(m-n)(m^2+mn+n^2)+1(m-n)]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/153204/gif.latex)
Simplify by combining like terms:

Begin by extracting from the polynomial:
Now, rearrange to combine like terms:
Extract the like terms and factor the cubic:
Simplify by combining like terms:
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Factor the following polynomial:

Factor the following polynomial:
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Begin by extracting
from the polynomial:


Now, rearrange to combine like terms:

Extract the like terms and factor the cubic:
![3[(x+1)(x^2-x+1)+3x(x+1)]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/153208/gif.latex)
Simplify by combining like terms:
![3[(x+1)(x^2-x+1+3x)]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/153209/gif.latex)



Begin by extracting from the polynomial:
Now, rearrange to combine like terms:
Extract the like terms and factor the cubic:
Simplify by combining like terms:
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