Help with Alkane Reactions - Organic Chemistry
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If an alkane is reacted with excess 
in a high temperature environment, what are the products formed?
If an alkane is reacted with excess
Tap to reveal answer
Whenever an alkane is reacted with excess oxygen in a high temperature reaction, the reaction is known as combustion. Combustion of an alkane always produces carbon dioxide gas and water vapor.
Therefore the correct answer is: 
and 
.
Whenever an alkane is reacted with excess oxygen in a high temperature reaction, the reaction is known as combustion. Combustion of an alkane always produces carbon dioxide gas and water vapor.
Therefore the correct answer is:
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Which of the following can reduce an alkene to an alkane?
Which of the following can reduce an alkene to an alkane?
Tap to reveal answer
Neither lithium aluminum hydride, nor sodium borohydride will reduce C–C double bonds.
H2/Raney nickel and H2/Pd can each (individually) reduce an alkene to an alkane. Since both H2/Raney nickel and H2/Pd can reduce the alkene, the answer is both of those reagents. This is a catalytic hydrogenation reaction, and H2/Raney nickel not only reduces C–C double bonds, but also carbonyl compounds.
Neither lithium aluminum hydride, nor sodium borohydride will reduce C–C double bonds.
H2/Raney nickel and H2/Pd can each (individually) reduce an alkene to an alkane. Since both H2/Raney nickel and H2/Pd can reduce the alkene, the answer is both of those reagents. This is a catalytic hydrogenation reaction, and H2/Raney nickel not only reduces C–C double bonds, but also carbonyl compounds.
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Identify the major organic product expected from the acid-catalyzed dehydration of 2-methyl-2-pentanol.
Identify the major organic product expected from the acid-catalyzed dehydration of 2-methyl-2-pentanol.
Tap to reveal answer
The initial compound is a five-carbon alkane chain with methyl and hydroxy groups on the second carbon. Dehydration involves the hydrogenation of the hydroxy group. That group then leaves, and a double bond is formed. Zaitsev's rule states that double bonds are more stable on more highly substituted carbons. The double bond forms across carbons two and three.
The initial compound is a five-carbon alkane chain with methyl and hydroxy groups on the second carbon. Dehydration involves the hydrogenation of the hydroxy group. That group then leaves, and a double bond is formed. Zaitsev's rule states that double bonds are more stable on more highly substituted carbons. The double bond forms across carbons two and three.
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If an alkane is reacted with excess in a high temperature environment, what are the products formed?
If an alkane is reacted with excess
Tap to reveal answer
Whenever an alkane is reacted with excess oxygen in a high temperature reaction, the reaction is known as combustion. Combustion of an alkane always produces carbon dioxide gas and water vapor.
Therefore the correct answer is: and .
Whenever an alkane is reacted with excess oxygen in a high temperature reaction, the reaction is known as combustion. Combustion of an alkane always produces carbon dioxide gas and water vapor.
Therefore the correct answer is:
← Didn't Know|Knew It →
Which of the following can reduce an alkene to an alkane?
Which of the following can reduce an alkene to an alkane?
Tap to reveal answer
Neither lithium aluminum hydride, nor sodium borohydride will reduce C–C double bonds.
H2/Raney nickel and H2/Pd can each (individually) reduce an alkene to an alkane. Since both H2/Raney nickel and H2/Pd can reduce the alkene, the answer is both of those reagents. This is a catalytic hydrogenation reaction, and H2/Raney nickel not only reduces C–C double bonds, but also carbonyl compounds.
Neither lithium aluminum hydride, nor sodium borohydride will reduce C–C double bonds.
H2/Raney nickel and H2/Pd can each (individually) reduce an alkene to an alkane. Since both H2/Raney nickel and H2/Pd can reduce the alkene, the answer is both of those reagents. This is a catalytic hydrogenation reaction, and H2/Raney nickel not only reduces C–C double bonds, but also carbonyl compounds.
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Identify the major organic product expected from the acid-catalyzed dehydration of 2-methyl-2-pentanol.
Identify the major organic product expected from the acid-catalyzed dehydration of 2-methyl-2-pentanol.
Tap to reveal answer
The initial compound is a five-carbon alkane chain with methyl and hydroxy groups on the second carbon. Dehydration involves the hydrogenation of the hydroxy group. That group then leaves, and a double bond is formed. Zaitsev's rule states that double bonds are more stable on more highly substituted carbons. The double bond forms across carbons two and three.
The initial compound is a five-carbon alkane chain with methyl and hydroxy groups on the second carbon. Dehydration involves the hydrogenation of the hydroxy group. That group then leaves, and a double bond is formed. Zaitsev's rule states that double bonds are more stable on more highly substituted carbons. The double bond forms across carbons two and three.
← Didn't Know|Knew It →
Which of the following can reduce an alkene to an alkane?
Which of the following can reduce an alkene to an alkane?
Tap to reveal answer
Neither lithium aluminum hydride, nor sodium borohydride will reduce C–C double bonds.
H2/Raney nickel and H2/Pd can each (individually) reduce an alkene to an alkane. Since both H2/Raney nickel and H2/Pd can reduce the alkene, the answer is both of those reagents. This is a catalytic hydrogenation reaction, and H2/Raney nickel not only reduces C–C double bonds, but also carbonyl compounds.
Neither lithium aluminum hydride, nor sodium borohydride will reduce C–C double bonds.
H2/Raney nickel and H2/Pd can each (individually) reduce an alkene to an alkane. Since both H2/Raney nickel and H2/Pd can reduce the alkene, the answer is both of those reagents. This is a catalytic hydrogenation reaction, and H2/Raney nickel not only reduces C–C double bonds, but also carbonyl compounds.
← Didn't Know|Knew It →
Identify the major organic product expected from the acid-catalyzed dehydration of 2-methyl-2-pentanol.
Identify the major organic product expected from the acid-catalyzed dehydration of 2-methyl-2-pentanol.
Tap to reveal answer
The initial compound is a five-carbon alkane chain with methyl and hydroxy groups on the second carbon. Dehydration involves the hydrogenation of the hydroxy group. That group then leaves, and a double bond is formed. Zaitsev's rule states that double bonds are more stable on more highly substituted carbons. The double bond forms across carbons two and three.
The initial compound is a five-carbon alkane chain with methyl and hydroxy groups on the second carbon. Dehydration involves the hydrogenation of the hydroxy group. That group then leaves, and a double bond is formed. Zaitsev's rule states that double bonds are more stable on more highly substituted carbons. The double bond forms across carbons two and three.
← Didn't Know|Knew It →
If an alkane is reacted with excess in a high temperature environment, what are the products formed?
If an alkane is reacted with excess
Tap to reveal answer
Whenever an alkane is reacted with excess oxygen in a high temperature reaction, the reaction is known as combustion. Combustion of an alkane always produces carbon dioxide gas and water vapor.
Therefore the correct answer is: and .
Whenever an alkane is reacted with excess oxygen in a high temperature reaction, the reaction is known as combustion. Combustion of an alkane always produces carbon dioxide gas and water vapor.
Therefore the correct answer is:
← Didn't Know|Knew It →
Which of the following can reduce an alkene to an alkane?
Which of the following can reduce an alkene to an alkane?
Tap to reveal answer
Neither lithium aluminum hydride, nor sodium borohydride will reduce C–C double bonds.
H2/Raney nickel and H2/Pd can each (individually) reduce an alkene to an alkane. Since both H2/Raney nickel and H2/Pd can reduce the alkene, the answer is both of those reagents. This is a catalytic hydrogenation reaction, and H2/Raney nickel not only reduces C–C double bonds, but also carbonyl compounds.
Neither lithium aluminum hydride, nor sodium borohydride will reduce C–C double bonds.
H2/Raney nickel and H2/Pd can each (individually) reduce an alkene to an alkane. Since both H2/Raney nickel and H2/Pd can reduce the alkene, the answer is both of those reagents. This is a catalytic hydrogenation reaction, and H2/Raney nickel not only reduces C–C double bonds, but also carbonyl compounds.
← Didn't Know|Knew It →
Identify the major organic product expected from the acid-catalyzed dehydration of 2-methyl-2-pentanol.
Identify the major organic product expected from the acid-catalyzed dehydration of 2-methyl-2-pentanol.
Tap to reveal answer
The initial compound is a five-carbon alkane chain with methyl and hydroxy groups on the second carbon. Dehydration involves the hydrogenation of the hydroxy group. That group then leaves, and a double bond is formed. Zaitsev's rule states that double bonds are more stable on more highly substituted carbons. The double bond forms across carbons two and three.
The initial compound is a five-carbon alkane chain with methyl and hydroxy groups on the second carbon. Dehydration involves the hydrogenation of the hydroxy group. That group then leaves, and a double bond is formed. Zaitsev's rule states that double bonds are more stable on more highly substituted carbons. The double bond forms across carbons two and three.
← Didn't Know|Knew It →
If an alkane is reacted with excess in a high temperature environment, what are the products formed?
If an alkane is reacted with excess
Tap to reveal answer
Whenever an alkane is reacted with excess oxygen in a high temperature reaction, the reaction is known as combustion. Combustion of an alkane always produces carbon dioxide gas and water vapor.
Therefore the correct answer is: and .
Whenever an alkane is reacted with excess oxygen in a high temperature reaction, the reaction is known as combustion. Combustion of an alkane always produces carbon dioxide gas and water vapor.
Therefore the correct answer is:
← Didn't Know|Knew It →