Algebraic Functions - PSAT Math

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Question

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

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Answer

The function f(x) is a piecewise function, which means that it is comprised of separate functions that change depending on the value of x. According to the problem, whenever x is less than 1, f(x) is defined by 2_x_ - 3. Whenever x is greater than or equal to one and less than 3, f(x) is defined as $4-x^2$ . And whenever x is greater than or equal to 3, f(x) is equal to |4_x_ – 9|.

The question asks us to find f(1) + f(3) + f(5). We need to calculate the values of f(1), f(3), and f(5) individually and then find their sum.

To find f(1), we must first decide which of the three possible functions for f(x) to use. Since f(1) means we are finding the value of f(x) when x = 1, we will have to use the second piece, which says that f(x) = $4-x^2$ . We can't use the function 2_x_ - 3, because this is only valid when x < 1, not when x = 1.

$f(1)=4-(1)^2=4-1 = 3$

Next, we will find f(3). We need to use the third piece of the function which states that f(x) = |4_x_ – 9|. Since f(3) means we are finding f(x) when x = 3, we can only use the third piece. The second piece, $4-x^2$ , is only defined if x is less than 3 and greater than or equal to 1.

$f(3)=|4x-9|=|4(3)-9|=|12-9|=|3|=3$

Lastly, we must find f(5). Again, we will use the function f(x) = |4_x_ – 9|, because when x = 5, x must be greater than 3.

$f(5)=|4(5)-9|=|20-9|=|11|=11$

We can now add up f(1), f(3), and f(5), which would give us 3 + 3 + 11 = 17.

The answer is 17.

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Question

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Tap to reveal answer

Answer

The function f(x) is a piecewise function, which means that it is comprised of separate functions that change depending on the value of x. According to the problem, whenever x is less than 1, f(x) is defined by 2_x_ - 3. Whenever x is greater than or equal to one and less than 3, f(x) is defined as $4-x^2$ . And whenever x is greater than or equal to 3, f(x) is equal to |4_x_ – 9|.

The question asks us to find f(1) + f(3) + f(5). We need to calculate the values of f(1), f(3), and f(5) individually and then find their sum.

To find f(1), we must first decide which of the three possible functions for f(x) to use. Since f(1) means we are finding the value of f(x) when x = 1, we will have to use the second piece, which says that f(x) = $4-x^2$ . We can't use the function 2_x_ - 3, because this is only valid when x < 1, not when x = 1.

$f(1)=4-(1)^2=4-1 = 3$

Next, we will find f(3). We need to use the third piece of the function which states that f(x) = |4_x_ – 9|. Since f(3) means we are finding f(x) when x = 3, we can only use the third piece. The second piece, $4-x^2$ , is only defined if x is less than 3 and greater than or equal to 1.

$f(3)=|4x-9|=|4(3)-9|=|12-9|=|3|=3$

Lastly, we must find f(5). Again, we will use the function f(x) = |4_x_ – 9|, because when x = 5, x must be greater than 3.

$f(5)=|4(5)-9|=|20-9|=|11|=11$

We can now add up f(1), f(3), and f(5), which would give us 3 + 3 + 11 = 17.

The answer is 17.

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Question

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Tap to reveal answer

Answer

The function f(x) is a piecewise function, which means that it is comprised of separate functions that change depending on the value of x. According to the problem, whenever x is less than 1, f(x) is defined by 2_x_ - 3. Whenever x is greater than or equal to one and less than 3, f(x) is defined as $4-x^2$ . And whenever x is greater than or equal to 3, f(x) is equal to |4_x_ – 9|.

The question asks us to find f(1) + f(3) + f(5). We need to calculate the values of f(1), f(3), and f(5) individually and then find their sum.

To find f(1), we must first decide which of the three possible functions for f(x) to use. Since f(1) means we are finding the value of f(x) when x = 1, we will have to use the second piece, which says that f(x) = $4-x^2$ . We can't use the function 2_x_ - 3, because this is only valid when x < 1, not when x = 1.

$f(1)=4-(1)^2=4-1 = 3$

Next, we will find f(3). We need to use the third piece of the function which states that f(x) = |4_x_ – 9|. Since f(3) means we are finding f(x) when x = 3, we can only use the third piece. The second piece, $4-x^2$ , is only defined if x is less than 3 and greater than or equal to 1.

$f(3)=|4x-9|=|4(3)-9|=|12-9|=|3|=3$

Lastly, we must find f(5). Again, we will use the function f(x) = |4_x_ – 9|, because when x = 5, x must be greater than 3.

$f(5)=|4(5)-9|=|20-9|=|11|=11$

We can now add up f(1), f(3), and f(5), which would give us 3 + 3 + 11 = 17.

The answer is 17.

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Question

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Tap to reveal answer

Answer

The function f(x) is a piecewise function, which means that it is comprised of separate functions that change depending on the value of x. According to the problem, whenever x is less than 1, f(x) is defined by 2_x_ - 3. Whenever x is greater than or equal to one and less than 3, f(x) is defined as $4-x^2$ . And whenever x is greater than or equal to 3, f(x) is equal to |4_x_ – 9|.

The question asks us to find f(1) + f(3) + f(5). We need to calculate the values of f(1), f(3), and f(5) individually and then find their sum.

To find f(1), we must first decide which of the three possible functions for f(x) to use. Since f(1) means we are finding the value of f(x) when x = 1, we will have to use the second piece, which says that f(x) = $4-x^2$ . We can't use the function 2_x_ - 3, because this is only valid when x < 1, not when x = 1.

$f(1)=4-(1)^2=4-1 = 3$

Next, we will find f(3). We need to use the third piece of the function which states that f(x) = |4_x_ – 9|. Since f(3) means we are finding f(x) when x = 3, we can only use the third piece. The second piece, $4-x^2$ , is only defined if x is less than 3 and greater than or equal to 1.

$f(3)=|4x-9|=|4(3)-9|=|12-9|=|3|=3$

Lastly, we must find f(5). Again, we will use the function f(x) = |4_x_ – 9|, because when x = 5, x must be greater than 3.

$f(5)=|4(5)-9|=|20-9|=|11|=11$

We can now add up f(1), f(3), and f(5), which would give us 3 + 3 + 11 = 17.

The answer is 17.

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Question

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Tap to reveal answer

Answer

The function f(x) is a piecewise function, which means that it is comprised of separate functions that change depending on the value of x. According to the problem, whenever x is less than 1, f(x) is defined by 2_x_ - 3. Whenever x is greater than or equal to one and less than 3, f(x) is defined as $4-x^2$ . And whenever x is greater than or equal to 3, f(x) is equal to |4_x_ – 9|.

The question asks us to find f(1) + f(3) + f(5). We need to calculate the values of f(1), f(3), and f(5) individually and then find their sum.

To find f(1), we must first decide which of the three possible functions for f(x) to use. Since f(1) means we are finding the value of f(x) when x = 1, we will have to use the second piece, which says that f(x) = $4-x^2$ . We can't use the function 2_x_ - 3, because this is only valid when x < 1, not when x = 1.

$f(1)=4-(1)^2=4-1 = 3$

Next, we will find f(3). We need to use the third piece of the function which states that f(x) = |4_x_ – 9|. Since f(3) means we are finding f(x) when x = 3, we can only use the third piece. The second piece, $4-x^2$ , is only defined if x is less than 3 and greater than or equal to 1.

$f(3)=|4x-9|=|4(3)-9|=|12-9|=|3|=3$

Lastly, we must find f(5). Again, we will use the function f(x) = |4_x_ – 9|, because when x = 5, x must be greater than 3.

$f(5)=|4(5)-9|=|20-9|=|11|=11$

We can now add up f(1), f(3), and f(5), which would give us 3 + 3 + 11 = 17.

The answer is 17.

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Question

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Tap to reveal answer

Answer

The function f(x) is a piecewise function, which means that it is comprised of separate functions that change depending on the value of x. According to the problem, whenever x is less than 1, f(x) is defined by 2_x_ - 3. Whenever x is greater than or equal to one and less than 3, f(x) is defined as $4-x^2$ . And whenever x is greater than or equal to 3, f(x) is equal to |4_x_ – 9|.

The question asks us to find f(1) + f(3) + f(5). We need to calculate the values of f(1), f(3), and f(5) individually and then find their sum.

To find f(1), we must first decide which of the three possible functions for f(x) to use. Since f(1) means we are finding the value of f(x) when x = 1, we will have to use the second piece, which says that f(x) = $4-x^2$ . We can't use the function 2_x_ - 3, because this is only valid when x < 1, not when x = 1.

$f(1)=4-(1)^2=4-1 = 3$

Next, we will find f(3). We need to use the third piece of the function which states that f(x) = |4_x_ – 9|. Since f(3) means we are finding f(x) when x = 3, we can only use the third piece. The second piece, $4-x^2$ , is only defined if x is less than 3 and greater than or equal to 1.

$f(3)=|4x-9|=|4(3)-9|=|12-9|=|3|=3$

Lastly, we must find f(5). Again, we will use the function f(x) = |4_x_ – 9|, because when x = 5, x must be greater than 3.

$f(5)=|4(5)-9|=|20-9|=|11|=11$

We can now add up f(1), f(3), and f(5), which would give us 3 + 3 + 11 = 17.

The answer is 17.

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Question

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Tap to reveal answer

Answer

The function f(x) is a piecewise function, which means that it is comprised of separate functions that change depending on the value of x. According to the problem, whenever x is less than 1, f(x) is defined by 2_x_ - 3. Whenever x is greater than or equal to one and less than 3, f(x) is defined as $4-x^2$ . And whenever x is greater than or equal to 3, f(x) is equal to |4_x_ – 9|.

The question asks us to find f(1) + f(3) + f(5). We need to calculate the values of f(1), f(3), and f(5) individually and then find their sum.

To find f(1), we must first decide which of the three possible functions for f(x) to use. Since f(1) means we are finding the value of f(x) when x = 1, we will have to use the second piece, which says that f(x) = $4-x^2$ . We can't use the function 2_x_ - 3, because this is only valid when x < 1, not when x = 1.

$f(1)=4-(1)^2=4-1 = 3$

Next, we will find f(3). We need to use the third piece of the function which states that f(x) = |4_x_ – 9|. Since f(3) means we are finding f(x) when x = 3, we can only use the third piece. The second piece, $4-x^2$ , is only defined if x is less than 3 and greater than or equal to 1.

$f(3)=|4x-9|=|4(3)-9|=|12-9|=|3|=3$

Lastly, we must find f(5). Again, we will use the function f(x) = |4_x_ – 9|, because when x = 5, x must be greater than 3.

$f(5)=|4(5)-9|=|20-9|=|11|=11$

We can now add up f(1), f(3), and f(5), which would give us 3 + 3 + 11 = 17.

The answer is 17.

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Question

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

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Answer

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

For the original relation, the range is: $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

Thus, the domain for the inverse relation will also be $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

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Question

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

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Answer

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

For the original relation, the range is: $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

Thus, the domain for the inverse relation will also be $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

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Question

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

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Answer

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

For the original relation, the range is: $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

Thus, the domain for the inverse relation will also be $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

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Question

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

Tap to reveal answer

Answer

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

For the original relation, the range is: $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

Thus, the domain for the inverse relation will also be $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

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Question

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

Tap to reveal answer

Answer

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

For the original relation, the range is: $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

Thus, the domain for the inverse relation will also be $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

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Question

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

Tap to reveal answer

Answer

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

For the original relation, the range is: $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

Thus, the domain for the inverse relation will also be $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

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Question

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

Tap to reveal answer

Answer

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

For the original relation, the range is: $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

Thus, the domain for the inverse relation will also be $\left \{ 2,\ 4,\ 6,\ 8 \right \}$ .

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Question

If f(x) = 5x – 10, then what is the value of 5(f(10)) – 10?

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Answer

The first step is to find what f(10) equals, so f(10)=5(10) – 10 = 40. Then substitute 40 into the second equation: 5(40) – 10 = 200 – 10 = 190.

190 is the correct answer

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Question

f(x) = 0.1x + 7

g(x) = 1000x + 4

What is g(f(100))?

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Answer

First find the value of f(100) = 0.1(100) + 7 = 10 + 7 = 17

Then find g(17) = 1000(17) + 4 = 17000 + 4 = 17004.

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Question

The rate of a gym membership costs p dollars the first month and m dollars per month every month thereafter. Which of the following represents the total cost of the gym membership for n months, if n is a positive integer?

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Answer

The one-time first-month cost is p, and the monthly cost is m, which gets multipled by every month but the first (of which there are n -1). The total cost is the first-month cost of p, plus the monthly cost for (i.e. times) n -1 months, which makes the total cost equal to p + m (n -1).

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Question

If f(x) = (x + 4)/(x – 4) for all integers except x = 4, which of the following has the lowest value?

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Answer

Plug each value for x into the above equation and solve for f(x). f(1) provides the lowest value –5/3

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Question

If n and p are positive and 100_n_3_p_-1 = 25_n_, what is n-2 in terms of p ?

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Answer

To solve this problem, we look for an operation to perform on both sides that will leave n-2 by itself on one side. Dividing both sides by 25_n_-3 would leave n-2 by itself on the right side of the equqation, as shown below:

100n3p–1/25n–3 = 25n/25n–3

Remember that when dividing terms with the same base, we subtract the exponents, so the equation can be written as 100n0p–1/25 = n–2

Finally, we simplify to find 4_p–_1 = _n–_2.

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Question

If 7y = 4x - 12, then x =

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Answer

Adding 12 to both sides and dividing by 4 yields (7y+12)/4.

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Algebraic Functions - PSAT Math

Let f(x) be defined as follows: What is the value of

Let f(x) be defined as follows: What is the value of

Let f(x) be defined as follows: What is the value of

Let f(x) be defined as follows: What is the value of

Let f(x) be defined as follows: What is the value of

Let f(x) be defined as follows: What is the value of

Let f(x) be defined as follows: What is the value of

Given the relation below, identify the domain of the inverse of the relation.

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse. For the original relation, the range is: . Thus, the domain for the inverse relation will also be .

Given the relation below, identify the domain of the inverse of the relation.

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse. For the original relation, the range is: . Thus, the domain for the inverse relation will also be .

Given the relation below, identify the domain of the inverse of the relation.

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse. For the original relation, the range is: . Thus, the domain for the inverse relation will also be .

Given the relation below, identify the domain of the inverse of the relation.

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse. For the original relation, the range is: . Thus, the domain for the inverse relation will also be .

Given the relation below, identify the domain of the inverse of the relation.

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse. For the original relation, the range is: . Thus, the domain for the inverse relation will also be .

Given the relation below, identify the domain of the inverse of the relation.

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse. For the original relation, the range is: . Thus, the domain for the inverse relation will also be .

Given the relation below, identify the domain of the inverse of the relation.

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse. For the original relation, the range is: . Thus, the domain for the inverse relation will also be .

If f(x) = 5x – 10, then what is the value of 5(f(10)) – 10?

The first step is to find what f(10) equals, so f(10)=5(10) – 10 = 40. Then substitute 40 into the second equation: 5(40) – 10 = 200 – 10 = 190. 190 is the correct answer

f(x) = 0.1x + 7 g(x) = 1000x + 4 What is g(f(100))?

First find the value of f(100) = 0.1(100) + 7 = 10 + 7 = 17 Then find g(17) = 1000(17) + 4 = 17000 + 4 = 17004.

The rate of a gym membership costs p dollars the first month and m dollars per month every month thereafter. Which of the following represents the total cost of the gym membership for n months, if n is a positive integer?

The one-time first-month cost is p, and the monthly cost is m, which gets multipled by every month but the first (of which there are n -1). The total cost is the first-month cost of p, plus the monthly cost for (i.e. times) n -1 months, which makes the total cost equal to p + m (n -1).

If f(x) = (x + 4)/(x – 4) for all integers except x = 4, which of the following has the lowest value?

Plug each value for x into the above equation and solve for f(x). f(1) provides the lowest value –5/3

If n and p are positive and 100_n_3_p_-1 = 25_n_, what is n-2 in terms of p ?

If 7y = 4x - 12, then x =

Adding 12 to both sides and dividing by 4 yields (7y+12)/4.

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Let f(x) be defined as follows:

$f(x)=\left\{\begin{matrix} 2x-3, &x<1 & \ 4-x^2, &1\leq x< 3 & \ |4x-9|, &x\geq 3 & \end{matrix}\right.$

What is the value of $f(1)+f(3)+f(5)?$

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

Given the relation below, identify the domain of the inverse of the relation.

$\left \{(1, 2), (3, 4), (5, 6), (7, 8){ \right \}$

The first step is to find what f(10) equals, so f(10)=5(10) – 10 = 40. Then substitute 40 into the second equation: 5(40) – 10 = 200 – 10 = 190.

190 is the correct answer

f(x) = 0.1x + 7

g(x) = 1000x + 4

What is g(f(100))?

First find the value of f(100) = 0.1(100) + 7 = 10 + 7 = 17

Then find g(17) = 1000(17) + 4 = 17000 + 4 = 17004.