Outcomes - SSAT Elementary Level Quantitative
Card 1 of 144
Joey has 10 shirts on his bed. 4 shirts are blue, 3 shirts are purple, 2 shirts are green, and 1 shirt is white. What is the chance that Joey randomly picks a purple shirt from the shirts on his bed?
Joey has 10 shirts on his bed. 4 shirts are blue, 3 shirts are purple, 2 shirts are green, and 1 shirt is white. What is the chance that Joey randomly picks a purple shirt from the shirts on his bed?
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To find the probability of picking a purple shirt from the pile of shirts on Joey's bed, we need to set up a fraction like this:

The problem tells us that Joey has 3 purple shirts, so we can put that in the numerator. We are also told that the total number of shirts on Joey's bed is 10, so 10 goes on the bottom of the fraction. Therefore, Joey has a
chance of picking a purple shirt.
To find the probability of picking a purple shirt from the pile of shirts on Joey's bed, we need to set up a fraction like this:
The problem tells us that Joey has 3 purple shirts, so we can put that in the numerator. We are also told that the total number of shirts on Joey's bed is 10, so 10 goes on the bottom of the fraction. Therefore, Joey has a chance of picking a purple shirt.
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A bag of marbles contains
green marbles,
blue marbles, and
red marbles.
If
marbles are taken from the bag on each draw, what is the greatest possible amount of draws that can occur without drawing a red marble?
A bag of marbles contains green marbles,
blue marbles, and
red marbles.
If marbles are taken from the bag on each draw, what is the greatest possible amount of draws that can occur without drawing a red marble?
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There are
green marbles and
red marbles in the bag. Adding these amounts together gives
marbles in the bag that are not red. If all
of these were drawn before any red marble, this would require
draws at
marbles per draw (
). Therefore, it is possible to draw up to
times without drawing a red marble.
There are green marbles and
red marbles in the bag. Adding these amounts together gives
marbles in the bag that are not red. If all
of these were drawn before any red marble, this would require
draws at
marbles per draw (
). Therefore, it is possible to draw up to
times without drawing a red marble.
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Sarah, Mitch, and Ben are going to a concert. If they are seated in a row of
, what fraction represents the probability Sarah will be seated in the middle of the row?
Sarah, Mitch, and Ben are going to a concert. If they are seated in a row of , what fraction represents the probability Sarah will be seated in the middle of the row?
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The number of total possible arrangements of three items in a row is
, or
.
We can write out all the possible arrangments and count the number in which Sarah sits in the middle.
-

-

-

-

-

-

In
out of
possible arrangements, Sarah sits in the middle. Expressed as a fraction, this is
, which is equivalent to
.
The number of total possible arrangements of three items in a row is , or
.
We can write out all the possible arrangments and count the number in which Sarah sits in the middle.
In out of
possible arrangements, Sarah sits in the middle. Expressed as a fraction, this is
, which is equivalent to
.
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Shannon has a box with 9 shirts inside. 4 shirts are pink, 3 shirts are yellow, 1 shirt is red, and 1 shirt is green. What is the probability that Shannon will randomly pick a pink shirt from the box?
Shannon has a box with 9 shirts inside. 4 shirts are pink, 3 shirts are yellow, 1 shirt is red, and 1 shirt is green. What is the probability that Shannon will randomly pick a pink shirt from the box?
Tap to reveal answer
To find the probability of picking a pink shirt from the box, we need to set up a fraction:
. The problem tells us that Shannon has 4 pink shirts, so we can put that on the top of the fraction. The total number of shirts is 9, which goes on the bottom of the fraction. That gives Shannon a
chance of picking a pink shirt from the box!
To find the probability of picking a pink shirt from the box, we need to set up a fraction: . The problem tells us that Shannon has 4 pink shirts, so we can put that on the top of the fraction. The total number of shirts is 9, which goes on the bottom of the fraction. That gives Shannon a
chance of picking a pink shirt from the box!
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Tucker is going fishing at a local pond with 15 fish. 5 fish are tuna, 4 fish are salmon, 3 fish are yellowtail, and 3 fish are trout. What is the chance that the first fish Tucker catches will be a tuna or a trout?
Tucker is going fishing at a local pond with 15 fish. 5 fish are tuna, 4 fish are salmon, 3 fish are yellowtail, and 3 fish are trout. What is the chance that the first fish Tucker catches will be a tuna or a trout?
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To find the probability of Tucker catching a tuna or a trout, we need to set up a fraction like this:
. The problem tells us that there are 5 tuna and 3 trout in the pond, so we can put 8 on the top of the fraction. The total number of fish in the pond is 15, so that goes on the bottom of the fraction. That gives Tucker an 8/15 chance of catching a tuna or trout!
To find the probability of Tucker catching a tuna or a trout, we need to set up a fraction like this: . The problem tells us that there are 5 tuna and 3 trout in the pond, so we can put 8 on the top of the fraction. The total number of fish in the pond is 15, so that goes on the bottom of the fraction. That gives Tucker an 8/15 chance of catching a tuna or trout!
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Josh has
cards in his hand. These cards are each red, yellow, or blue. If
of the cards are red and
are yellow, what is the probability of drawing a blue card?
Josh has cards in his hand. These cards are each red, yellow, or blue. If
of the cards are red and
are yellow, what is the probability of drawing a blue card?
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Of the
cards Josh has in his hand,
are red and
are yellow. We need to figure out how many blue cards Josh must have in his hand. We are told that each of the cards in Josh's hand is either red, yellow, or blue, so if a card is not red or yellow, it is blue. Since
cards that are red or yellow, the rest of the cards must be blue.
, so there must be
blue cards in Josh's hand. The total number of cards is
, so the chance of drawing a blue card is
.
Of the cards Josh has in his hand,
are red and
are yellow. We need to figure out how many blue cards Josh must have in his hand. We are told that each of the cards in Josh's hand is either red, yellow, or blue, so if a card is not red or yellow, it is blue. Since
cards that are red or yellow, the rest of the cards must be blue.
, so there must be
blue cards in Josh's hand. The total number of cards is
, so the chance of drawing a blue card is
.
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Mikey has a box of chocolates. 5 chocolates have a caramel filling, 6 chocolates have an almond filling, 3 chocolates have no filling, and 1 chocolate has a cherry filling. If Mikey selects a chocolate from the box at random, what is the chance that he selects a chocolate with a filling?
Mikey has a box of chocolates. 5 chocolates have a caramel filling, 6 chocolates have an almond filling, 3 chocolates have no filling, and 1 chocolate has a cherry filling. If Mikey selects a chocolate from the box at random, what is the chance that he selects a chocolate with a filling?
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To find the probability of Mikey selecting a piece of chocolate with a filling from the box of chocolates, we need to set up a fraction like this:
.
The problem tells us that we have 5 chocolates with a caramel filling, 6 chocolates with an almond filling, and 1 chocolate with a cherry filling. We need to add them all together to find out how many chocolates have any type of filling, and place that number on top of the above fraction.

Now, we need to add 3 more to the above number because the box has 3 chocolates with no filling, and then use that new number as our denominator (on the bottom of the fraction).

That gives Mikey a 12/15 chance of picking a filled chocolate from the box of chocolates!
To find the probability of Mikey selecting a piece of chocolate with a filling from the box of chocolates, we need to set up a fraction like this: .
The problem tells us that we have 5 chocolates with a caramel filling, 6 chocolates with an almond filling, and 1 chocolate with a cherry filling. We need to add them all together to find out how many chocolates have any type of filling, and place that number on top of the above fraction.
Now, we need to add 3 more to the above number because the box has 3 chocolates with no filling, and then use that new number as our denominator (on the bottom of the fraction).
That gives Mikey a 12/15 chance of picking a filled chocolate from the box of chocolates!
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Niall has a box of 6 scarves. 3 scarves are purple, 2 scarves are blue, and 1 scarf is white. What is the chance that Niall will randomly pick a blue scarf from the box?
Niall has a box of 6 scarves. 3 scarves are purple, 2 scarves are blue, and 1 scarf is white. What is the chance that Niall will randomly pick a blue scarf from the box?
Tap to reveal answer
To find the probability of picking a blue scarf from the box, we need to set up a fraction like this:
. The problem tells us that Niall has 2 blue scarves, so we can put that on the top of the fraction. The problem also tells us that Niall has a total of 6 scarves, so we can put that on the bottom of the fraction. That gives Niall a
chance of picking a blue scarf from the box!
To find the probability of picking a blue scarf from the box, we need to set up a fraction like this: . The problem tells us that Niall has 2 blue scarves, so we can put that on the top of the fraction. The problem also tells us that Niall has a total of 6 scarves, so we can put that on the bottom of the fraction. That gives Niall a
chance of picking a blue scarf from the box!
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Harvey has a bouquet of 12 flowers: 5 are lilacs, 3 are roses, 2 are orchids, and 2 are dandelions. What is the chance that Harvey randomly selects a rose from the bouquet?
Harvey has a bouquet of 12 flowers: 5 are lilacs, 3 are roses, 2 are orchids, and 2 are dandelions. What is the chance that Harvey randomly selects a rose from the bouquet?
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To find the probability of Harvey picking a rose from the bouquet of flowers, we need to set up a fraction like this:

The problem tells us that Harvey has 3 roses, so we can put that on the top of the fraction. The problem also tells us that Harvey has 12 total flowers, so we can put that on the bottom of the fraction. That gives Harvey a
chance of picking a rose from the bouquet!
Since
is not an answer choice, we need to reduce the fraction. To reduce a fraction means to divide the top (numerator) and the bottom (denominator) by a common factor that both numbers share. The numbers 3 and 12 both have a common factor of 3, so we can divide the top and the bottom by 3 to get the correct answer of
.
To find the probability of Harvey picking a rose from the bouquet of flowers, we need to set up a fraction like this:
The problem tells us that Harvey has 3 roses, so we can put that on the top of the fraction. The problem also tells us that Harvey has 12 total flowers, so we can put that on the bottom of the fraction. That gives Harvey a chance of picking a rose from the bouquet!
Since is not an answer choice, we need to reduce the fraction. To reduce a fraction means to divide the top (numerator) and the bottom (denominator) by a common factor that both numbers share. The numbers 3 and 12 both have a common factor of 3, so we can divide the top and the bottom by 3 to get the correct answer of
.
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Mary has a bag with
cookies.
cookies are chocolate chip,
cookies are sugar, and
cookies are oatmeal raisin. What is the chance that Mary randomly selects a sugar cookie from the bag?
Mary has a bag with cookies.
cookies are chocolate chip,
cookies are sugar, and
cookies are oatmeal raisin. What is the chance that Mary randomly selects a sugar cookie from the bag?
Tap to reveal answer
To find the probability of Mary picking a sugar cookie from the bag of cookies, we need to set up a fraction like this:
.
The problem tells us that Mary has
sugar cookies, so we can put that on the top of the fraction. The problem also tells us that Mary has
total cookies, so we can put that on the bottom of the fraction. That gives Mary a
chance of picking a sugar cookie.

Since
is not an answer choice, we need to reduce the fraction. To reduce a fraction means to divide the top (numerator) and the bottom (denominator) by a common factor that both numbers share. The numbers
and
both have a common factor of
, so we can divide the top and the bottom by
to get the correct answer of
.

To find the probability of Mary picking a sugar cookie from the bag of cookies, we need to set up a fraction like this: .
The problem tells us that Mary has sugar cookies, so we can put that on the top of the fraction. The problem also tells us that Mary has
total cookies, so we can put that on the bottom of the fraction. That gives Mary a
chance of picking a sugar cookie.
Since is not an answer choice, we need to reduce the fraction. To reduce a fraction means to divide the top (numerator) and the bottom (denominator) by a common factor that both numbers share. The numbers
and
both have a common factor of
, so we can divide the top and the bottom by
to get the correct answer of
.
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Selena has a standard deck of cards. What is the chance that she randomly selects a red card from the deck?
Selena has a standard deck of cards. What is the chance that she randomly selects a red card from the deck?
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To find the probability of Selena picking a red card from a standard deck of cards, we need to set up a fraction like this:
.
A standard deck of cards has 52 cards, 26 of which are black and 26 of which are red. Our fraction looks like this:

We can reduce the fraction, since both numbers share a common factor.

To find the probability of Selena picking a red card from a standard deck of cards, we need to set up a fraction like this: .
A standard deck of cards has 52 cards, 26 of which are black and 26 of which are red. Our fraction looks like this:
We can reduce the fraction, since both numbers share a common factor.
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A piggy bank contains an assortment of quarters, dimes, nickels, and pennies. Assuming all coins are equally likely to be picked, if there are
pennies,
nickels,
dimes, and
quarters, what is the probability of drawing a quarter out of the bank?
A piggy bank contains an assortment of quarters, dimes, nickels, and pennies. Assuming all coins are equally likely to be picked, if there are pennies,
nickels,
dimes, and
quarters, what is the probability of drawing a quarter out of the bank?
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Adding together all of the numbers,
total coins. Since there are
quarters, the probability of drawing a quarter is
, which can be simplified to
.
Adding together all of the numbers, total coins. Since there are
quarters, the probability of drawing a quarter is
, which can be simplified to
.
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Malcolm is on vacation with his family. He packed five shirts and five pairs of shorts. There are three white shirts, one black shirt, and one blue shirt. There are two blue pairs of shorts, one yellow pair of shorts, one black pair of shorts, and one red pair of shorts. If Malcolm reached into his suitcase and pulled out an article of clothing, what is the probability that it is either blue or black?
Malcolm is on vacation with his family. He packed five shirts and five pairs of shorts. There are three white shirts, one black shirt, and one blue shirt. There are two blue pairs of shorts, one yellow pair of shorts, one black pair of shorts, and one red pair of shorts. If Malcolm reached into his suitcase and pulled out an article of clothing, what is the probability that it is either blue or black?
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We know that there are 10 articles of clothing (5 shirts and 5 pairs of shorts). First, you need to determine how many of these shirts and shorts are either blue or black. The problem says Malcolm has one black shirt, one blue shirt, two blue pairs of shorts, and one black pair of shorts.

This means he has a 5 in 10 chance of picking clothing that is blue or black.

We know that there are 10 articles of clothing (5 shirts and 5 pairs of shorts). First, you need to determine how many of these shirts and shorts are either blue or black. The problem says Malcolm has one black shirt, one blue shirt, two blue pairs of shorts, and one black pair of shorts.
This means he has a 5 in 10 chance of picking clothing that is blue or black.
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In a regular deck of cards, what is the probability of flipping up a diamond?
In a regular deck of cards, what is the probability of flipping up a diamond?
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There are
cards in a regular deck. There are
clubs,
diamonds,
hearts, and
spades.
The probability is the amount of diamonds over the total amount of cards.
The probability is: 
There are cards in a regular deck. There are
clubs,
diamonds,
hearts, and
spades.
The probability is the amount of diamonds over the total amount of cards.
The probability is:
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What is the probability of flipping a coin twice and land on tails both times?
What is the probability of flipping a coin twice and land on tails both times?
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Flipping a coin the first time is independent of the second time.
The probability of getting tails on the first try is: 
The probability of getting tails on the second try is: 
Multiply the probabilities.

The correct answer is: 
Flipping a coin the first time is independent of the second time.
The probability of getting tails on the first try is:
The probability of getting tails on the second try is:
Multiply the probabilities.
The correct answer is:
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A bag contains 3 green marbles, 1 red marble, 4 blue marbles, and 2 white marbles. What is the probability of pulling out a white marble?
A bag contains 3 green marbles, 1 red marble, 4 blue marbles, and 2 white marbles. What is the probability of pulling out a white marble?
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To solve, simply divide the derside number of outcomes by the total number of outcomes.
The desired outcome is white marbles and the total number of outcomes is the total number of marbles.
Thus,

To solve, simply divide the derside number of outcomes by the total number of outcomes.
The desired outcome is white marbles and the total number of outcomes is the total number of marbles.
Thus,
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If you roll a fair die, what is the probability that you an even number?
If you roll a fair die, what is the probability that you an even number?
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A fair die has
sides so there are that many possible options.
There are
even numbers on a die
.
That means the probability of getting an even number is
or
.
A fair die has sides so there are that many possible options.
There are even numbers on a die
.
That means the probability of getting an even number is or
.
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Johnny has 3 blue marbles, 4 red marbles and 10 white marbles. What is the probability that Johnny will choose a blue marble?
Johnny has 3 blue marbles, 4 red marbles and 10 white marbles. What is the probability that Johnny will choose a blue marble?
Tap to reveal answer
Probability can generally be described by the equation below.

In this case, we must first understand that the part is just the blue marbles, there are 3 of them.

We also must add up all the marbles to find the total for the "whole."

When we plug in the "part" and the "whole" below we get:

Probability can generally be described by the equation below.
In this case, we must first understand that the part is just the blue marbles, there are 3 of them.
We also must add up all the marbles to find the total for the "whole."
When we plug in the "part" and the "whole" below we get:
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Ethan has a bag with 20 of his favorite marbles. He has 5 blue marbles, 7 red marbles, 2 white ones, 4 black ones, and 2 multi-colored marbles. What is the probability that he randomly picks a red marble out of the bag?
Ethan has a bag with 20 of his favorite marbles. He has 5 blue marbles, 7 red marbles, 2 white ones, 4 black ones, and 2 multi-colored marbles. What is the probability that he randomly picks a red marble out of the bag?
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The probability is expressed as the circumstance out of the whole number available.
The number of marbles that are red is 7, and the whole number of marbles is 20.
Therefore the probability is
.
The probability is expressed as the circumstance out of the whole number available.
The number of marbles that are red is 7, and the whole number of marbles is 20.
Therefore the probability is
.
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What is the probability of drawing a Queen from a deck of cards?
What is the probability of drawing a Queen from a deck of cards?
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To find the probability of an event happening, we use the following

So, if we look at the number of ways we can draw a Queen, we can come up with
- Queen of Hearts
- Queen of Diamonds
- Queen of Spades
- Queen of Clubs
So, the number of ways we can draw a queen is equal to 4. So,

Now, to find the total number of possible outcomes, we will think of how many different cards there are within a deck. We know there are 52 total cards, which means there are 52 total possible outcomes. So,

Now, we can simplify.



To find the probability of an event happening, we use the following
So, if we look at the number of ways we can draw a Queen, we can come up with
- Queen of Hearts
- Queen of Diamonds
- Queen of Spades
- Queen of Clubs
So, the number of ways we can draw a queen is equal to 4. So,
Now, to find the total number of possible outcomes, we will think of how many different cards there are within a deck. We know there are 52 total cards, which means there are 52 total possible outcomes. So,
Now, we can simplify.
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