Basic Addition, Subtraction, Multiplication and Division - SSAT Upper Level: Quantitative
Card 1 of 160
You are asked to fill in both circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
You are asked to fill in both circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
Tap to reveal answer
The problem is asking for a number whose square is a number congruent to 1 in modulo 12 arithmetic - that is, a number whose square, when divided by 12, yields remainder 1. This square must be odd, so the number squared must also be odd. Therefore, we need only test the odd integers. We see that:
Four of the integers have squares congruent to 1 in modulo 12 arithmetic.
The problem is asking for a number whose square is a number congruent to 1 in modulo 12 arithmetic - that is, a number whose square, when divided by 12, yields remainder 1. This square must be odd, so the number squared must also be odd. Therefore, we need only test the odd integers. We see that:
Four of the integers have squares congruent to 1 in modulo 12 arithmetic.
← Didn't Know|Knew It →
You are asked to fill in both circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
You are asked to fill in both circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
Tap to reveal answer
The problem is asking for a number whose square is a number congruent to 1 in modulo 12 arithmetic - that is, a number whose square, when divided by 12, yields remainder 1. This square must be odd, so the number squared must also be odd. Therefore, we need only test the odd integers. We see that:
Four of the integers have squares congruent to 1 in modulo 12 arithmetic.
The problem is asking for a number whose square is a number congruent to 1 in modulo 12 arithmetic - that is, a number whose square, when divided by 12, yields remainder 1. This square must be odd, so the number squared must also be odd. Therefore, we need only test the odd integers. We see that:
Four of the integers have squares congruent to 1 in modulo 12 arithmetic.
← Didn't Know|Knew It →
You are asked to fill in all three circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
You are asked to fill in all three circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
Tap to reveal answer
The problem is asking for a number whose cube is a number congruent to 9 in modulo 10 arithmetic - that is, a number whose cube, when divided by 10, yields remainder 9. If the quotient of a number and 10 has remainder 9, then it is an integer that ends with the digit "9". Since this makes the cube odd, the number that is cubed must also be odd, so we need only test the five odd integers:
Only 9 fits the criterion, so "one" is the correct response.
The problem is asking for a number whose cube is a number congruent to 9 in modulo 10 arithmetic - that is, a number whose cube, when divided by 10, yields remainder 9. If the quotient of a number and 10 has remainder 9, then it is an integer that ends with the digit "9". Since this makes the cube odd, the number that is cubed must also be odd, so we need only test the five odd integers:
Only 9 fits the criterion, so "one" is the correct response.
← Didn't Know|Knew It →
You are asked to fill in both circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
You are asked to fill in both circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
Tap to reveal answer
The problem is asking for a number whose square is a number congruent to 1 in modulo 12 arithmetic - that is, a number whose square, when divided by 12, yields remainder 1. This square must be odd, so the number squared must also be odd. Therefore, we need only test the odd integers. We see that:
Four of the integers have squares congruent to 1 in modulo 12 arithmetic.
The problem is asking for a number whose square is a number congruent to 1 in modulo 12 arithmetic - that is, a number whose square, when divided by 12, yields remainder 1. This square must be odd, so the number squared must also be odd. Therefore, we need only test the odd integers. We see that:
Four of the integers have squares congruent to 1 in modulo 12 arithmetic.
← Didn't Know|Knew It →
You are asked to fill in all three circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
You are asked to fill in all three circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
Tap to reveal answer
The problem is asking for a number whose cube is a number congruent to 9 in modulo 10 arithmetic - that is, a number whose cube, when divided by 10, yields remainder 9. If the quotient of a number and 10 has remainder 9, then it is an integer that ends with the digit "9". Since this makes the cube odd, the number that is cubed must also be odd, so we need only test the five odd integers:
Only 9 fits the criterion, so "one" is the correct response.
The problem is asking for a number whose cube is a number congruent to 9 in modulo 10 arithmetic - that is, a number whose cube, when divided by 10, yields remainder 9. If the quotient of a number and 10 has remainder 9, then it is an integer that ends with the digit "9". Since this makes the cube odd, the number that is cubed must also be odd, so we need only test the five odd integers:
Only 9 fits the criterion, so "one" is the correct response.
← Didn't Know|Knew It →
You are asked to fill in all three circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
You are asked to fill in all three circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
Tap to reveal answer
The problem is asking for a number whose cube is a number congruent to 9 in modulo 10 arithmetic - that is, a number whose cube, when divided by 10, yields remainder 9. If the quotient of a number and 10 has remainder 9, then it is an integer that ends with the digit "9". Since this makes the cube odd, the number that is cubed must also be odd, so we need only test the five odd integers:
Only 9 fits the criterion, so "one" is the correct response.
The problem is asking for a number whose cube is a number congruent to 9 in modulo 10 arithmetic - that is, a number whose cube, when divided by 10, yields remainder 9. If the quotient of a number and 10 has remainder 9, then it is an integer that ends with the digit "9". Since this makes the cube odd, the number that is cubed must also be odd, so we need only test the five odd integers:
Only 9 fits the criterion, so "one" is the correct response.
← Didn't Know|Knew It →
You are asked to fill in all three circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
You are asked to fill in all three circles in the statement
with the same number from the set
to make a true statement.
How many ways can you do this?
Tap to reveal answer
The problem is asking for a number whose cube is a number congruent to 9 in modulo 10 arithmetic - that is, a number whose cube, when divided by 10, yields remainder 9. If the quotient of a number and 10 has remainder 9, then it is an integer that ends with the digit "9". Since this makes the cube odd, the number that is cubed must also be odd, so we need only test the five odd integers:
Only 9 fits the criterion, so "one" is the correct response.
The problem is asking for a number whose cube is a number congruent to 9 in modulo 10 arithmetic - that is, a number whose cube, when divided by 10, yields remainder 9. If the quotient of a number and 10 has remainder 9, then it is an integer that ends with the digit "9". Since this makes the cube odd, the number that is cubed must also be odd, so we need only test the five odd integers:
Only 9 fits the criterion, so "one" is the correct response.
← Didn't Know|Knew It →
Tap to reveal answer
First, convert 
into a decimal. We are left with
Now add the three numbers, being careful to line the decimal points up exactly. From right to left we will add:
-
4 and 5 = 9
-
5, 2, and 2 = 9
-
2 is alone = 2
This leaves us with 2.99 for the final answer.
First, convert
Now add the three numbers, being careful to line the decimal points up exactly. From right to left we will add:
-
4 and 5 = 9
-
5, 2, and 2 = 9
-
2 is alone = 2
This leaves us with 2.99 for the final answer.
← Didn't Know|Knew It →
Tap to reveal answer
Use order of operations, so you would first complete the operation in the parentheses, which would give you 
.
Then you do exponenets, so 
.
Then you do division which is 
.
Then you do addition from left to right, so 
.
Last, you add 
to 
, which is 
.
Use order of operations, so you would first complete the operation in the parentheses, which would give you
Then you do exponenets, so
Then you do division which is
Then you do addition from left to right, so
Last, you add
← Didn't Know|Knew It →
What is the sum of the two percentages in decimal form?
7 percent and 135 percent
What is the sum of the two percentages in decimal form?
7 percent and 135 percent
Tap to reveal answer
You add the percentages and you get 142 percent. To convert a percent to a decimal, you divide by 100, so the answer is 1.42.
You add the percentages and you get 142 percent. To convert a percent to a decimal, you divide by 100, so the answer is 1.42.
← Didn't Know|Knew It →
Which of the following angles is supplementary to an angle that is 45 degrees?
Which of the following angles is supplementary to an angle that is 45 degrees?
Tap to reveal answer
Supplementary angles add up to 180 degrees. Given that 
, the correct answer is 135.
Supplementary angles add up to 180 degrees. Given that
← Didn't Know|Knew It →
Tap to reveal answer
Do the expression in the parantheses and you get 
. Then you do 
and you get 
. Then you do 
and you get 
. Then you add 
.
Do the expression in the parantheses and you get
← Didn't Know|Knew It →
If Susie bought a pair of shoes for 
, a shirt for 
, and a pair of pants for 
. How much did she spend in total?
If Susie bought a pair of shoes for
Tap to reveal answer
You add all three values and you get 
.
You add all three values and you get
← Didn't Know|Knew It →
and 
are prime integers. 
and 
. What is the greatest possible value of 
?
Tap to reveal answer
To find the greatest possible value of 
, add the greatest possible value of 
to the greatest possible value of 
. This happens when 
is equal to the greatest prime between 35 and 45, which is 43, and when 
is equal to the greatest prime between 85 and 95, which is 89. Add the two numbers:
To find the greatest possible value of
← Didn't Know|Knew It →
and are prime integers: 
and 
. How many possible values of 
are there?
Tap to reveal answer
can be equal to any of the prime numbers between 45 and 55, of which there are two - 47 or 53.
can be equal to any of the prime numbers between 15 and 25, of which there are three - 17, 19, and 23.
Their sum can be any of the following:
This makes five possible sums.
Their sum can be any of the following:
This makes five possible sums.
← Didn't Know|Knew It →
In a math contest, the team from Lincoln High comprised five students - Melanie, Ned, Olivia, Phyllis, and Quinn. Melanie outscored Ned by 12 points; Ned outscored Quinn by 19 points; Phyllis outscored Ned by 45 points and Olivia by 20 points. Who came in third among the five?
In a math contest, the team from Lincoln High comprised five students - Melanie, Ned, Olivia, Phyllis, and Quinn. Melanie outscored Ned by 12 points; Ned outscored Quinn by 19 points; Phyllis outscored Ned by 45 points and Olivia by 20 points. Who came in third among the five?
Tap to reveal answer
Since this reasoning is valid regardless of the actual scores, suppose Quinn scored 100. Then Ned scored 19 more than Quinn, or 119, and Melanie scored 12 more than Ned, or 131. Phyllis scored 45 more than Ned, or 164, and Olivia scored 20 points fewer than Phyllis, or 144. This makes the order, from greatest to least:
Phyllis, Olivia, Melanie, Ned, Quinn
Melanie scored third among the five.
Since this reasoning is valid regardless of the actual scores, suppose Quinn scored 100. Then Ned scored 19 more than Quinn, or 119, and Melanie scored 12 more than Ned, or 131. Phyllis scored 45 more than Ned, or 164, and Olivia scored 20 points fewer than Phyllis, or 144. This makes the order, from greatest to least:
Phyllis, Olivia, Melanie, Ned, Quinn
Melanie scored third among the five.
← Didn't Know|Knew It →
Simplify: 
Simplify:
Tap to reveal answer
To simplify this expression, regroup and combine like-terms.
To simplify this expression, regroup and combine like-terms.
← Didn't Know|Knew It →
Divide:
Divide:
Tap to reveal answer
We can write 18 pounds, 2 ounces as just ounces as follows:
Divide:
Convert 58 ounces to pounds and ounces as follows:
That is, 3 pounds 10 ounces.
We can write 18 pounds, 2 ounces as just ounces as follows:
Divide:
Convert 58 ounces to pounds and ounces as follows:
That is, 3 pounds 10 ounces.
← Didn't Know|Knew It →
Simplify by rationalizing the denominator:
Simplify by rationalizing the denominator:
Tap to reveal answer
Multiply both numerator and denominator by the conjugate of the denominator, which is 
:
Multiply both numerator and denominator by the conjugate of the denominator, which is
← Didn't Know|Knew It →
Simplify by rationalizing the denominator:
Simplify by rationalizing the denominator:
Tap to reveal answer
Multiply both numerator and denominator by the conjugate of the denominator, which is 
:
Multiply both numerator and denominator by the conjugate of the denominator, which is
← Didn't Know|Knew It →