Proportionality

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Texas 7th Grade Math › Proportionality

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1

A circle has diameter 8 inches and circumference 25.12 inches

How does the ratio $C/d$ compare to $\pi$?

Less than $\pi$

0

About half of $\pi$

0

About twice $\pi$

0

Approximately equal to $\pi$

CORRECT

Explanation

$\pi$ is the constant ratio $C/d$ for any circle. Compute $C/d = 25.12/8 = 3.14 \approx 3.14159 = \pi$. Thus the ratio is approximately equal to $\pi$, showing why $\pi$ underlies circle measurements.

2

A coin was flipped 20 times and landed on heads 13 times and tails 7 times. Predict results for 100 trials.

About 65 heads and 35 tails

CORRECT

About 50 heads and 50 tails

0

About 70 heads and 30 tails

0

About 13 heads and 7 tails

0

Explanation

Use the experimental proportion. Heads were $13/20=0.65$, so in 100 flips expect about $0.65\times 100=65$ heads and $35$ tails. The theoretical probability is $1/2$ each, but experimental results can vary due to randomness.

3

Event A: It rains tomorrow. The probability of rain tomorrow is 0.35. What is $P(\text{not }A)$?

0.35

0

0.75

0

0.65

CORRECT

1.35

0

Explanation

Use complements: $P(\text{not }A)=1-P(A)=1-0.35=0.65$. Check: $0.35+0.65=1$.

4

Triangle ABC has sides 6, 8, 10 cm. Triangle DEF has sides 9, 12, 15 cm. Are these triangles similar?

Yes, because 6:9 = 8:12 = 10:15

CORRECT

No, because they are not congruent

0

No, because their perimeters are different

0

Yes, because both are triangles

0

Explanation

Similar figures have the same shape with corresponding sides in equal ratios. Order the sides from least to greatest to match: 6↔9, 8↔12, 10↔15. Compute ratios: 6/9=2/3, 8/12=2/3, 10/15=2/3. All corresponding ratios are equal, so the triangles are similar.

5

A basketball player makes a free throw about 70% of the time. You want to simulate one free throw. Which simulation best models this?

Flip a fair coin; heads = made, tails = missed.

0

Roll a fair number cube; 1–4 = made, 5–6 = missed.

0

Spin an 8-section spinner; 6 shaded = made, 2 unshaded = missed.

0

Use random digits 0–9; 0–6 = made, 7–9 = missed.

CORRECT

Explanation

Using digits 0–9 gives 10 equally likely outcomes, and marking 7 of them as made matches $7/10 = 70%$. The others model $1/2$, $4/6$, or $6/8$, which are $50%$, about $66.7%$, and $75%$, not $70%$.

6

On a blueprint with scale 1:50, a room measures 6 cm by 8 cm. What are the actual room dimensions?

0.12 m × 0.16 m

0

3 m × 4 m

CORRECT

30 m × 40 m

0

3.6 m × 4.8 m

0

Explanation

The linear scale factor is $k=50$. Actual lengths: 6×50=300 cm=3 m and 8×50=400 cm=4 m. So 3 m × 4 m. Distractors divide by 50, confuse cm-to-m conversion, or use the wrong factor.

7

A random sample of 80 teenagers shows 32 prefer streaming music. The city has 50,000 teenagers. How many in the whole population likely prefer streaming?

20000

CORRECT

16000

0

32000

0

50000

0

Explanation

Use the sample proportion: $32/80 = 0.40$. Scale to the population: $0.40 \times 50{,}000 = 20{,}000$. Because this is based on a random sample, it is an estimate and the actual number may differ slightly.

8

A bag has 4 blue, 3 red, and 5 green marbles. What is $P(\text{blue})$ on one draw? Structure: single draw from a bag; without replacement (single draw).

$4/7$

0

$1/3$

CORRECT

$3/12$

0

$5/12$

0

Explanation

Favorable outcomes: 4 blue. Total outcomes: $4+3+5=12$. So $P(\text{blue})=\frac{4}{12}=\frac{1}{3}$.

9

A fair coin was flipped 200 times and landed on heads 116 times. What is the experimental probability of heads?

0.42

0

0.58

CORRECT

0.5

0

1.16

0

Explanation

Use heads/total: $116/200 = 0.58 = 58%$. Experimental results can vary from trial to trial, but with more flips the result tends to get closer to 50%.

10

A number cube labeled 1–6 is rolled, then a coin is flipped. Write outcomes as (number, coin). Which list shows all outcomes?

(1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (5,H), (5,T), (6,H)

0

(1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T)

CORRECT

(H,1), (T,1), (H,2), (T,2), (H,3), (T,3), (H,4), (T,4), (H,5), (T,5), (H,6), (T,6)

0

(1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,H)

0

Explanation

There are 6 numbers and 2 coin results, so $6 \times 2 = 12$ outcomes. List systematically by number: for each 1–6, pair with H and T to get all 12: (1,H), (1,T), …, (6,H), (6,T).