Calculate the curl for the following vector field.
$curl \ \vec{F}=\Big(-2yz^2+x^2y\Big)\vec{i}+\Big(-x\Big)\vec{j}+\Big(-2xyz\Big)\vec{k}$
$curl \ \vec{F}=\Big(2yz^2-x^2y\Big)\vec{i}+\Big(x\Big)\vec{j}+\Big(2xyz\Big)\vec{k}$
$curl \ \vec{F}=\Big(-x^2y\Big)\vec{i}+\Big(-x\Big)\vec{j}+\Big(xyz\Big)\vec{k}$
$curl \ \vec{F}=\Big(2yz^2\Big)\vec{i}+\Big(z\Big)\vec{j}+\Big(2xz\Big)\vec{k}$
$curl\ \vec{F}=\Big(4x^2y^3z^3\Big)\vec{i}+\Big(2xz^2\Big)\vec{j}+\Big(-2xy^3z^4+2x^3y\Big)\vec{k}$
$curl\ \vec{F}=\Big(2x^2z^3\Big)\vec{i}+\Big(2yz^2\Big)\vec{j}+\Big(-2x^3y\Big)\vec{k}$
$curl\ \vec{F}=\Big(-4x^2y^3z^3\Big)\vec{i}+\Big(-2xz^2\Big)\vec{j}+\Big(2xy^3z^4-2x^3y\Big)\vec{k}$
