Simplify:
$(xy^2)^2+3x^2y^4$
$2x^2y^4$
$4x^2y^4$
$3x^2y^4$
$x^2y^4$
$4x^4y^4$
Solve for B
AX+B(2Y)=C
B=4
Not enough information provided.
$\frac{C-2Y}{AX}=B$
$B=\frac{C-AX}{2Y}$
$2B=\frac{C-AX}{Y}$
