Using Limits with Continuity Practice Test

$\lim_{x\rightarrow 1} h(x)$ does not exist because $f (1 ) \neq \lim_{x\rightarrow 1^{-}} h(x)$

$\lim_{x\rightarrow 1} h(x)$ exists because $\lim_{x\rightarrow 1^{-}} | h(x)| = \lim_{x\rightarrow 1^{+}} |h(x)|$

$\lim_{x\rightarrow 1} h(x)$ does not exist because $\lim_{x\rightarrow 1^{-}} h(x) \neq \lim_{x\rightarrow 1^{+}} h(x)$.

$\lim_{x\rightarrow 1} h(x)$ does not exist because $f (1 ) \neq \lim_{x\rightarrow 1^{+}} h(x)$

$\lim_{x\rightarrow 1} h(x)$ exists because $f (1 ) = \frac{\lim_{x\rightarrow 1^{-}} h(x) + \lim_{x\rightarrow 1^{+ }} h(x)}{2}$