Simplify:
$\frac{8x^3y^2z^2}{4xy^4z^3}$
$2x^4y^6z^4$
$2x^2y^2z$
$\frac{2x^2}{y^2z}$
$\frac{y^2z}{2x^2}$
If f(x) = x - 3, then find $f^{-1}(x)$
$f^{-1}(x)=x+3$
$f^{-1}(x)=\frac{1}{x-3}$
$f^{-1}(x)=3-x$
$f^{-1}(x)=x-3$
$f^{-1}(x)=3x$
